[英]How to capitalize each alternate character of a string?
可以說有一個字符串“ johngoestoschool”,它應該變成“ JoHnGoEsToScHoOl”,如果它們之間有特殊字符,則應該忽略它,例如給定字符串“ jo $%@#hn ^ g oe!st#os&ch oo)l ”答案應為“ Jo $%@#Hn ^ G oE!sT#oS&cH oO)l”
從這個答案中,我們可以迭代來做:
let s = "alpha"
for i in s.characters.indices[s.startIndex..<s.endIndex]
{
print(s[i])
}
為什么我們不能在此處打印“ i”的值? 當我們執行i.customPlaygroundQuickLook時,它將int 0鍵入為int4。
所以我的想法是
if (i.customPlaygroundQuickLook == 3) {
s.characters.currentindex = capitalized
}
請幫助
這應該可以解決您的功能,困難的部分只是檢查天氣字符是否為字母,使用inout
和replace范圍將提供更好的性能:
func altCaptalized(string: String) -> String {
var stringAr = string.characters.map({ String($0) }) // Convert string to characters array and mapped it to become array of single letter strings
var numOfLetters = 0
// Convert string to array of unicode scalar character to compare in CharacterSet
for (i,uni) in string.unicodeScalars.enumerated() {
//Check if the scalar character is in letter character set
if CharacterSet.letters.contains(uni) {
if numOfLetters % 2 == 0 {
stringAr[i] = stringAr[i].uppercased() //Replace lowercased letter with uppercased
}
numOfLetters += 1
}
}
return stringAr.joined() //Combine all the single letter strings in the array into one string
}
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