如何在sql中將行從一個臨時表插入到另一個

Question

    ID  LogDate      LogTime           InoutMode    
    1   2017-02-23  19:30:00.0000000    1   
    2   2017-02-23  20:00:00.0000000    0   
    3   2017-02-23  20:30:00.0000000    1   
    4   2017-02-23  21:00:00.0000000    0   
    5   2017-02-23  21:30:00.0000000    1   
    6   2017-02-24  08:00:00.0000000    0   

以上結果來自臨時表。現在我想將 LogTime 插入到另一個臨時表中，如下所示。

      InOutMode-1 =>InTime
      InOutMode-0 =>OutTime

     InTime            OutTime
   19:30:00.0000000   20:00:00.0000000
   20:30:00.0000000   21:00:00.0000000
   21:30:00.0000000   08:00:00.0000000

Answer 1

要將一個表的行插入到另一個表中，您可以編寫以下 SQL 查詢：

INSERT INTO anotherTemp (InTime)
    SELECT LogTime
    FROM Temp
    WHERE InoutMode = 1  

INSERT INTO anotherTemp (OutTime)
    SELECT LogTime
    FROM Temp
    WHERE InoutMode = 0 

有關更多信息，請參閱此鏈接http://www.dofactory.com/sql/insert-into

Answer 2

使用INSERT INTO .. SELECT FROM構造像

insert into #temp2
select ID, LogDate, 
case when InoutMode = 1 then LogTime end as InTime, 
case when InoutMode = 0 then LogTime end as OutTime,
InoutMode    
from #temp1

Answer 3

使用 2 個InoutMode ，一個用於InoutMode和1 ，另一個用於0並根據Id列或日期和時間列的順序給InoutMode號。 然后加入這 2 個 cte。

詢問

;with cte as(
    select [rn] = row_number() over(
        order by [Id] -- also order by [LogDate], [LogTime]
    ), *
    from #your_temp_table_name
    where [InoutMode] = 1
),
cte2 as(
    select [rn] = row_number() over(
        order by [Id] -- also order by [LogDate], [LogTime]
    ), *
    from #your_temp_table_name
    where [InoutMode] = 0
)
select 
    t1.[LogTime] [InTime],
    t2.[LogTime] [OutTime]
from cte t1
left join cte2 t2
on t1.[rn] = t2.[rn];

如果要將結果集放入新的臨時表中。 然后最后一部分可以修改為

select 
    t1.[LogTime] [InTime],
    t2.[LogTime] [OutTime] 
into #your_new_temp_table_name
from cte t1
left join cte2 t2
on t1.[rn] = t2.[rn];

在這里找到演示