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[英]Spring jpa hibernate how to map a relationship to multiple objects of the same entity
[英]Hibernate - relationship from multiple fields to same entity
我有實體FooDetails,它具有兩個字段:客戶和位置列表。 客戶具有地址(@OneToOne單向映射),而位置也具有具有@OneToOne映射的地址。
碰巧“客戶”和“位置”中的“地址”相同。 所有這些對象都來自遠程服務,在保存之前,我手動將遠程對象的ID放入實體中。 映射如下所示:
@Entity
@Table(name = "FOO")
public class FooDetails {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "id")
private long id;
@OneToOne(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
@JoinColumn(name = "customer_id")
private Customer customer;
@OneToMany(cascade = CascadeType.ALL)
@JoinColumn(name = "details_id")
private Set<Location> locationList;
...
}
@Entity
@Table(name = "CUSTOMER")
public class Customer {
@Id
@Column(name = "customer_id", unique = true)
private long customerId;
@OneToOne(cascade = CascadeType.ALL)
@JoinColumn(name = "address_id")
private Address address;
...
}
@Entity
@Table(name = "LOCATION")
public class Location {
@Id
@Column(name = "location_id", unique = true)
private long locationId;
@OneToOne(cascade = CascadeType.ALL)
@JoinColumn(name = "address_id")
private Address address;
...
}
@Entity
@Table(name = "ADDRESS")
public class Address{
@Id
@Column(name = "address_id")
private long addressId;
...
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (!(o instanceof StawareAddress)) return false;
StawareAddress that = (StawareAddress) o;
return addressId == that.addressId;
}
@Override
public int hashCode() {
return (int) (addressId ^ (addressId >>> 32));
}
}
當我從Web服務接收整個FooDetails對象時,我嘗試將其保存到本地數據庫。
如果數據庫是干凈的(尚未保存地址),則會保存一個來自WS且具有正確ID的地址。 如果已經有一個具有此ID的地址,則Hibernate會嘗試將新的ID插入數據庫,並且由於對addressId的唯一約束,將出現錯誤。
我正在使用Spring Data Jpa保存實體(save()方法)。
我錯過了哪些明顯的實體映射問題?
我實際上不鼓勵在這里使用CascadeType.ALL
並手動處理它。
public void saveFoodetails(FooDetails fooDetails) {
Address address = addressRepository.find( fooDetails.getAddress().getId() );
if ( address != null ) {
// perhaps you update address with data from fooDetails.getAddress()
addressRepository.save( address );
// associate attached address instance with fooDetails now.
fooDetails.setAddress( address );
}
else {
// save the new incoming address contained in FooDetails
addressRepository.save( fooDetails.getAddress() );
}
// now save/update FooDetails
fooDetailsRepository.save( fooDetails );
}
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