對象內部的Map數組

Question

我有以下復雜的JSON對象，該對象在一個數組內有一個array和一個array。 如何解析這些數組並為數組中的每個元素創建一個對象數組。 我在項目中使用lodash庫，以防萬一有可用的功能。

   {
  studentId: 123
  name: XYZ
  phone: 34234234
  gender: M
  subjects: [{
     studentId: 123
     subjectName: Math
     scores:50
    assignments:[
     {
        type: Internal,
        submitted: yes,
        status: failed 
     },
     {
        type: External,
        submitted: yes,
        status: passed 
     }] 
},
{
     studentId: 123
     subjectName: Science
     score: 20
     assignments:[
     {
        type: Internal,
        submitted: yes,
        status: passed 
     },
     {
        type: External,
        submitted: yes,
        status: failed 
     }]
}] 

}

期望：

[{
  studentId:123,
  name: XYZ
  phone: 34234234
  gender: M,  
  subjectName: Math
  scores:50
  assignments:[
     {
        type: Internal,
        submitted: yes,
        status: failed 
     },
     {
        type: External,
        submitted: yes,
        status: passed 
     }]
},
{
 studentId:123,
  name: XYZ
  phone: 34234234
  gender: M,  
  subjectName: science
  scores:20
  assignments:[
     {
        type: Internal,
        submitted: yes,
        status: failed 
     },
     {
        type: External,
        submitted: yes,
        status: passed 
     }]
}
]

Answer 1

您可以使用省略來獲取沒有subjects數組的學生的details ，使用這些details通過map使用默認值來轉換主體數組中的每個項目。

var details = _.omit(data, 'subjects');
var result = _.map(data.subjects, function(subject) {
  return _.defaults({}, details, subject);
});

 var data = { studentId: '123', name: 'XYZ', phone: '34234234', gender: 'M', subjects: [{ studentId: '123', subjectName: 'Math', scores: 50, assignments: [{ type: 'Internal', submitted: 'yes', status: 'failed' }, { type: 'External', submitted: 'yes', status: 'passed' } ] }, { studentId: '123', subjectName: 'Science', score: 20, assignments: [{ type: 'Internal', submitted: 'yes', status: 'passed' }, { type: 'External', submitted: 'yes', status: 'failed' } ] } ] }; var details = _.omit(data, 'subjects'); var result = _.map(data.subjects, function(subject) { return _.defaults({}, details, subject); }); console.log(result); 

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 <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.js"></script> 

Answer 2

我鼓勵您使用Normalizr軟件包。 這非常有用，即使您的收藏是嵌套的，也能照顧到您。