[英]How use UPDATE in CONCAT() of PROCEDURE MySQL
我嘗試通過PROCEDURE更新存在表。 但是我收到一個錯誤:MySQL:#1064-您的SQL語法有錯誤; 檢查與MySQL服務器版本相對應的手冊,以在第1行的'= iOS, phone_manufacture
= Apple, phone_model
= iPhone, os_vers
= iOS XX'附近使用正確的語法
我的程序:
BEGIN
DECLARE a, b INT;
DECLARE a1, a2, a3, a4 TEXT;
DECLARE cur1 CURSOR FOR SELECT id FROM z7_group;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET b = 1;
OPEN cur1;
SET b = 0;
SET a1 = "iOS";
SET a2 = "Apple";
SET a3 = "iPhone";
SET a4 = "iOS X.X";
WHILE b = 0 DO
FETCH cur1 INTO a;
IF b = 0 THEN
SET @data_ all_group = (SELECT `myTables` FROM `all_group` WHERE id= a);
SET @s = CONCAT('UPDATE ', @data_ all_group, 'SET `os` = ',a1,', `phone_manufacture` = ',a2,', `phone_model` = ',a3', `os_vers` = ',a4,');
PREPARE stmt3 FROM @s;
EXECUTE stmt3;
END IF;
END WHILE;
CLOSE cur1;
END;
您有兩種選擇:(還有更多選擇,但我認為這是您想要的)
初始化時將值括在單引號中:
SET a1 = "'iOS'"; SET a2 = "'Apple'"; SET a3 = "'iPhone'"; SET a4 = "'iOS X.X'";
並修改句子:
CONCAT('UPDATE ', @data_all_group, ' SET `os` = ',a1,', `phone_manufacture` = ',a2,', `phone_model` = ',a3,', `os_vers` = ',a4)
結果將是:
UPDATE your_table SET `os` = 'iOS', `phone_manufacture` = 'Apple', `phone_model` = 'iPhone', `os_vers` = 'iOS XX'
或者:修復查詢版本:
SET @s = CONCAT('UPDATE ', @data_all_group , "SET `os` = '" , a1 ,"'," , "`phone_manufacture` = '",a2,"'," , "`phone_model` = '",a3,"'," , "`os_vers` = '",a4,"'");
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