如何在Python中將帶有'X'的字符串填充到最小長度？

Question

最近，在我的GCSE計算機科學課程中，我們被要求編寫一個程序，該程序將一個人的名字和姓氏放在一個字符串中，然后接受名字的首字母和姓氏的前四個字母並打印出來。 ，如果用戶的姓氏長度不超過一個字符，它將用字母'X'代替空格。

在考試中，我們不允許訪問互聯網，因此我在不使用互聯網的情況下開發了該程序，但是現在我想知道是否有更簡便的方法來編寫我編寫的程序。

while True:
    fullname = input("\nPlease type in your firstname and your surname: ")

    space = fullname.index(" ")
    length = len(fullname)
    x = "X"

    endsur = length - 1
    initialfirst = fullname[0]

    fullsurname = endsur - space

    if fullsurname >= 4:
        startsur = space + 1
        secondsur = space + 2
        thirdsur = space + 3
        fourthsur = space+ 4

        surname = fullname[startsur] + fullname[secondsur] + fullname[thirdsur] + fullname[fourthsur]

        print(initialfirst,surname)

        again = input("\nWould you like to go again? (Y/N)")

        if again == "y":
            continue
        if again == "n":
            print("Goodbye!")
            quit()

    if fullsurname == 3:
        startsur = space + 1
        secondsur = space + 2
        thirdsur = space + 3

        surname = fullname[startsur] + fullname[secondsur] + fullname[thirdsur] + x

        print(initialfirst,surname)

        again = input("\nWould you like to go again? (Y/N)")

        if again == "y":
            continue
        if again == "n":
            print("Goodbye!")
            quit()

    if fullsurname == 2:
        startsur = space + 1
        secondsur = space + 2

        surname = fullname[startsur] + fullname[secondsur] + x + x

        if again == "y":
            continue
        if again == "n":
            print("Goodbye!")
            quit()

    if fullsurname == 1:
        startsur = space + 1

        surname = fullname[startsur] + x + x + x

        if again == "y":
            continue
        if again == "n":
            print("Goodbye!")
            quit()

    if fullsurname <= 0:
        print("\nIt looks like you've not put in your surname. Please make sure to use a space between your firstname and your surname.")

Answer 1

while True:
    name = input('What is your name? ')
    name = name.split(' ')
    first_name = name[0]
    last_name = name[1]

    if len(last_name) < 4:
        last_name += 'x'*(4-len(last_name))

    together = first_name[0] + last_name[0:4]

    #You can add your error checks here
    print(together)

    cont = input('Would you like to go again? ')
    if cont == 'y':
        pass
    else:
        break

Answer 2

這段代碼是@Wright的答案的附加內容：提示：避免創建不必要的變量來進一步壓縮代碼，並避免命名空間泛濫

while 1:
    first_name, last_name  = input('What is your name? ').split(' ')
    if len(last_name) < 4:
        last_name += 'x'*(4-len(last_name))   
    together = first_name[0] + last_name[0:4]
    print(together)
    if input('Would you like to go again? ') != 'y':
        break

Answer 3

print("Enter your firstname and your surname (ex. Christopher Brown)")

while True:
    name = input('> ').split()
    if name == ['q']:
        exit()
    elif len(name) < 2:
        print("Invalid input")
        continue

    print(name[0][0],name[1][:4 if len(name[1]) >= 4 else len(name[1])]+'X'*(4-len(name[1])))

我為您大大縮短了代碼，我將獲取名稱的所有輸入移到一行中的一個變量中，然后進行了檢查並從一行中打印了所有內容，不客氣！！！

Answer 4

確保姓氏具有足夠字符的最簡單方法是首先添加'XXXX'填充。

fullname = input(…)
firstname, surname_x = (fullname + "XXXX").split()
print(firstname[0], surname_x[:4])

Answer 5

您也可以為此使用Python的字符串格式 。

while True:
    name = input('What is your name? ')
    print('{:.1}{:x<4.4}'.format(*name.split(' ', 1)))
    if input('Would you like to go again? ') != 'y':
        break

.1和.4表示名字和第二名將被截斷，而x<4表示應該用x s填充第二名。