[英]yes or no to exit a switch statement
是否可以創建yes或no函數以退出switch
語句。 如果(y)es被擊中,它將退出。 如果(n)o被擊中,它將循環返回到開關的選項。 如果是這樣,將如何進行。 到目前為止,這就是我所擁有的。
我希望這有助於闡明我要做什么
int yes_no(void) {
scanf("%d", &option);
while (option == 'y' || option == 'Y' || option == 'n' || option == 'N') {
if (option == 'y' || option == 'Y') {
return 1;
} else
if (option == 'n' || option == 'N') {
return 0;
} else {
printf("Only (Y)es or (N)o are acceptable");
}
}
}
int main(void) {
int select;
do {
printf("0 exit");
printf("1 hello");
scanf("%d", &select);
switch (select) {
case 0:
printf("Exit the program? (Y)es or (N)o :");
yes_no(); // if (n)o is hit it will loop back to the menu
break;
case 1:
printf("hello how r u doing");
break;
default:
printf("not accepted number");
}
} while (select != 0);
}
考慮以下yes_no
函數。
int yes_no() {
char option;
while (1) {
printf("(y/n): ");
if (scanf(" %c", &option) != 1) {
printf("Error occurred while reading option.\n");
continue;
}
if (option == 'y' || option == 'Y') {
return 1;
} else if (option == 'n' || option == 'N') {
return 0;
} else {
printf("Only (y)es or (n)o are acceptable.\n");
}
}
}
如果輸入為yes
,則返回值為1
如果為no
,則返回值為0
。 考慮到這一點,在switch
語句的代碼塊為case 0
的case 0
,可以捕獲此函數的返回值,然后將其用於中斷循環或不執行任何操作。 例如:
int main(void) {
int select;
int continue_loop = 1;
printf("Press 0 to exit\n");
printf("Press 1 for hello\n\n");
while (continue_loop) {
printf("(0/1): ");
if (scanf(" %d", &select) != 1) {
printf("Error occurred while reading number.\n");
continue;
}
switch (select) {
case 0:
printf("Exit the program? (y)es or (n)o;\n");
int make_sure = yes_no(); // yes_no() returns 1 if 'yes', and 0 if 'no'
// If 'yes', break while loop by setting continue_loop to 0.
// Do nothing in case of 'no'
if (make_sure == 1) {
continue_loop = 0;
}
break;
case 1:
printf("Hello, how are you doing?\n");
break;
default:
printf("Number not accepted.\n");
}
}
return 0;
}
如果我正確地回答了您的問題,這應該可以完成工作:
int yes_or_no()
{
do
{
char option = 0;
scanf(" %c", &option);
if (option == 'y' || option == 'Y')
return 1;
if (option == 'n' || option == 'N')
return 0;
printf("Only (Y)es or (N)o are acceptable");
}
while( 1 );
}
使用switch可以更好地執行代碼:
int yes_no(void) {
scanf("%d", &option);
while (1){
switch(option){
case 'y':
case 'Y':
return 1;
case 'n':
case 'N':
return 0;
default:
printf("invalid input.try again");
scanf("%d", &option);
}
}
}
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