[英]Get each day of the week as columns MySQL and PHP
我正在用PHP編寫PHP的Web應用程序。
我有一個名為count的表,這是數據存儲在該表中的方式:
Table: counts id counts location_id media_id created_at -------------------------------------------------- 1 50 1 1 2017-03-15 2 30 2 1 2017-03-15 3 80 1 2 2017-03-15 4 20 1 1 2017-03-16 5 100 2 2 2017-03-16
對於每個唯一的location_id,media_id和created_at,我存儲計數。
我有另一個表位置,如下所示:
Table: locations id name ---------------- 1 Location 1 2 Location 2 3 Location 3 4 Location 4 5 Location 5
這是我目前的SQL查詢:
select sum(counts.count) as views, locations.name as locations, DAYNAME(counts.created_at) AS weekday from `counts` inner join `locations` on `locations`.`id` = `counts`.`location_id` where `counts`.`created_at` between '2016-12-04' and '2016-12-10' group by `weekday`, `counts`.`location_id`;
這是數據的顯示方式:
locations weekday views ----------------------------------- Location 1 Mon 50 Location 1 Tue 30 Location 2 Mon 20 Location 2 Tue 70
我正在創建報告,並且我想運行一個查詢,以便一周中的所有日子都顯示為一列,其相應的值作為一周中該日的查看計數。 我想要這樣的東西:
locations mon tue wed thu fri sat sun ------------------------------------------------- Location 1 40 60 51 20 40 20 30 Location 2 80 60 100 24 30 10 5
以上是可能在MySQL或我將不得不使用PHP來實現這一點? 如果是這樣,我該怎么做呢?
任何幫助將不勝感激,謝謝。
注意:樣本數據不准確。
使用條件聚合可以使用MySQL實現此結果。
訣竅是在SELECT列表中的表達式中使用條件測試來確定是否返回count值。
像這樣的東西:
SELECT l.name AS `locations`
, SUM(IF(DATE_FORMAT(c.created_at,'%a')='Mon',c.count,0)) AS `mon`
, SUM(IF(DATE_FORMAT(c.created_at,'%a')='Tue',c.count,0)) AS `tue`
, SUM(IF(DATE_FORMAT(c.created_at,'%a')='Wed',c.count,0)) AS `wed`
, SUM(IF(DATE_FORMAT(c.created_at,'%a')='Thu',c.count,0)) AS `thu`
, SUM(IF(DATE_FORMAT(c.created_at,'%a')='Fri',c.count,0)) AS `fri`
, SUM(IF(DATE_FORMAT(c.created_at,'%a')='Sat',c.count,0)) AS `sat`
, SUM(IF(DATE_FORMAT(c.created_at,'%a')='Sun',c.count,0)) AS `sun`
FROM `locations` l
LEFT
JOIN `counts` c
ON c.location_id = l.id
AND c.created_at >= '2016-12-04'
AND c.created_at < '2016-12-04' + INTERVAL 7 DAY
GROUP BY l.name
ORDER BY l.name
注意:
對於樣本數據, location_id=1 and created_at='2016-03-15'
有兩行,因此該查詢將返回總計130(對於tue
(= 50 + 80),而不是50(如示例中所示)輸出現有查詢)。
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