MySQL如何在1個查詢中選擇具有2個不同where條件的求和列

Question

+-----+---------+--------+---------+
| PID | account | amount | balance |
+-----+---------+--------+---------+
|   1 |       1 |    100 |      dr |
|   2 |       5 |    100 |      cr |
|   3 |       2 |     30 |      dr |
|   4 |       1 |     30 |      cr |
|   5 |       1 |     50 |      cr |
|   6 |       4 |     50 |      dr |
+-----+---------+--------+---------+

我有上面的示例表，我正在使用CI，我想選擇“列值WHERE列余額具有值dr”的總和減去“列值WHERE列余額具有值cr”的總和。 現在如何將其寫到一個查詢中？

我目前正在使用2個查詢，如下所示

// Get total amount that has balance dr of account 1
$this->db->select_sum('amount');
$query = $this->db->get_where('table', array('account' => '1', 'balance' => 'dr');
$result = $query->result();
$total_dr = $result[0] -> amount;

// Get total amount that has balance cr of account 1
$this->db->select_sum('amount');
$query = $this->db->get_where('table', array('account' => '1', 'balance' => 'cr');
$result = $query->result();
$total_cr = $result[0] -> amount;

// Minus total_dr to total_cr
$total = $total_dr - $total_cr;

我認為必須有一種方法來獲得$ total而不查詢兩次，但是我找不到SO的線索。

Answer 1

SELECT
   account,
   SUM(CASE WHEN balance = 'dr' THEN amount
      WHEN balance = 'cr' THEN -amount
      ELSE 0
      END
   ) amount
FROM
   table
GROUP BY
   account

Answer 2

您可以使用SQL查詢來做到這一點：

SELECT 
    SUM(CASE WHEN balance = 'dr' THEN amount ELSE NULL END) AS sum_dr,
    SUM(CASE WHEN balance = 'cr' THEN amount ELSE NULL END) AS sum_cr
FROM table
WHERE account = 1
AND balance IN ('dr', 'cr')

將上面的查詢放入CI query（）方法並從結果數組中獲取列：“ sum_dr”和“ sum_cr”。

Answer 3

這樣的事情應該可以解決問題：

SELECT SUM(IF(balance = 'dr', amount, (-1) * amount))
FROM table
WHERE account = 1
AND balance IN ('dr', 'cr')