[英]Client sending a file to server via socket
我編寫了一個客戶端和一個服務器程序,其中客戶端將文件發送到服務器,服務器打印文件的內容。 這是代碼片段:
Server---------------->serverprog.py
import socket
from threading import *
class Server:
gate = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host = socket.gethostname()
port = 0
file = ''
def __init__(self, port):
self.port = port
# self.gate.bind((self.host, self.port))
self.gate.bind(("127.0.0.1", self.port))
self.listen()
def listen(self):
self.gate.listen(10)
while True:
conn,address = self.gate.accept()
self.receiveFilename(conn)
def receiveFileName(self, sock):
buf = sock.recv(1024)
print('First bytes I got: ' + buf)
a = Server(8888)
Client ------------------>clientprog.py
import socket
from threading import *
class Client:
gateway = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
#host = socket.gethostname()
host = ''
port = 0
file = ''
def __init__(self, host, port, file):
self.port = port
self.host = host
self.file = file
self.connect()
def connect(self):
self.gateway.connect((self.host, self.port))
self.sendFileName()
self.sendFile()
def sendFileName(self):
self.gateway.send("name:" + self.file)
def sendFile(self):
readByte = open(self.file, "rb")
data = readByte.read()
readByte.close()
self.gateway.send(data)
self.gateway.close()
a = Client('127.0.0.1', 8888, 'datasend.txt')
如果同時編譯客戶端和服務器,則服務器程序將出現以下錯誤:
Traceback (most recent call last):
File "receivefilepg.py", line 25, in <module>
a = Server(8888)
File "receivefilepg.py", line 15, in __init__
self.listen()
File "receivefilepg.py", line 20, in listen
self.receiveFilename(conn)
AttributeError: Server instance has no attribute 'receiveFilename'
我在這里做錯了什么? 任何的意見都將會有幫助!
該錯誤告訴您所有您需要了解的信息, server.listen
方法中有一個錯字,而不是調用了self.receiveFileName
調用self.receiveFilename
。
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