為什么廚師配方中的最后一條命令首先執行？

Question

我在無業游民的centos-72 Chef 12.19.36中運行

在metadata.rb中depends 'rabbitmq', '~> 3.0'

我嘗試的run_list

 "recipe[rabbitmq]",
 "recipe[rabbitmq::mgmt_console]",
 "recipe[rabbitmq::user_management]",
 "recipe[mycookbook::myrecipe]"

我的食譜是

chef_gem 'rabbitmq_http_api_client' do
  version                    '1.8.0'
  action                     :install
end

require "rabbitmq/http/client"
endpoint = "http://127.0.0.1:15672"
client = RabbitMQ::HTTP::Client.new(endpoint, :username => "user", :password => "321")
client.declare_exchange("myvhost", "myexchange", durable: true, type: "direct")

沒有myrecipe，一切都會好的。 但是，如果我將myrecipe添加到運行列表的末尾，則其內容將在其余食譜之前開始運行，並且當然會出現Failed to open TCP connection to 127.0.0.1:15672 (Connection refused - connect(2) for "127.0.0.1" port 15672)

現在我用這段代碼解決了這個問題，但是我不喜歡這樣，也不理解為什么在Rabbitmq安裝之前運行clarify_exchange

include_recipe 'rabbitmq'

rabbitmq_plugin 'rabbitmq_management' do
  action :enable
end

rabbitmq_user 'user' do
  password "321"
  action :add
end

rabbitmq_vhost 'myvhost' do
  action :add
end

rabbitmq_user 'user' do
  vhost 'myvhost'
  permissions ".* .* .*"
  action :set_permissions
end


rabbitmq_user 'user' do
  tag 'administrator'
  action :set_tags
end

rabbitmq_user "guest" do
  action :delete
  notifies :run, 'ruby_block[declare_rmq_exchange]'
end

chef_gem 'rabbitmq_http_api_client' do
  version                    '1.8.0'
  action                     :install
end

require "rabbitmq/http/client"
endpoint = "http://127.0.0.1:15672"

ruby_block 'declare_rmq_exchange' do
  block do
    client = RabbitMQ::HTTP::Client.new(endpoint, :username => "user", :password => "321")
    client.declare_exchange("myvhost", "myexchange", durable: true, type: "direct")
  end
  action :nothing
end

Answer 1

這是由廚師-客戶兩階段模型引起的。 首先，執行ruby代碼（ 編譯階段 ），然后執行已定義資源的實現（例如rabbitmq_user或chef_gem ）（ 收斂階段 ）。

在編譯階段執行對RabbitMQ::HTTP::Client.new調用時，將在用戶設置之前首先執行它。

將此代碼包裝在ruby_block資源中，以便按預期順序執行。