如何將此查詢轉換為DQL學說

Question

SELECT apntoken,deviceid,created 
FROM `distribution_mobiletokens` as dm
WHERE userid='20'
and not exists (
    select 1 
    from `distribution_mobiletokens`
    where userid = '20'
    and deviceid = dm.deviceid
    and created > dm.created
    )

該查詢的作用是選擇用戶ID等於20並且設備ID相同的所有移動代幣，但選擇設備的最新apn代幣。

我的數據庫如下所示。

有關此查詢的更多信息，我從我在這里提出的另一個問題中獲得了此答案（ 如何在SQL中按最大日期對分組（按分組排序） ）

我嘗試過的事情

$mobiletokens = $em->createQueryBuilder()
          ->select('u.id,company.id as companyid,user.id as userid,u.apntoken')
          ->from('AppBundle:MobileTokens', 'u')
          ->leftJoin('u.companyId', 'company')
          ->leftJoin('u.userId', 'user')
          ->where('u.status = 1 and user.id = :userid')
          ->setParameter('userid',(int)$jsondata['userid'])
          ->groupby('u.apntoken')
          ->getQuery()
          ->getResult();

       //@JA - Get the list of all the apn tokens we need to send the message to.
       foreach($mobiletokens as $tokenobject){
           $deviceTokens[] = $tokenobject["apntoken"];
           echo $tokenobject["apntoken"]."\n";
       }

        die();

這給了我錯誤的回應

63416A61F2FD47CC7B579CAEACB002CB00FACC3786A8991F329BB41B1208C4BA
9B25BBCC3F3D2232934D86A7BC72967A5546B250281FB750FFE645C8EB105AF6
latestone

感謝您的幫助！

其他資訊

SELECT * FROM數據

使用SQL之后，我提供了數據。

Answer 1

我現在只是暫時解決此問題，雖然不確定這是否是最佳答案。

$em = $this->em;

       $connection = $em->getConnection();
       $statement = $connection->prepare("
            SELECT apntoken,deviceid,created 
            FROM `distribution_mobiletokens` as dm
            WHERE userid=:userid
            and not exists (
                select 1 
                from `distribution_mobiletokens`
                where userid = :userid
                and deviceid = dm.deviceid
                and created > dm.created
            )");
       $statement->bindValue('userid', $jsondata['userid']);
       $statement->execute();

       $mobiletokens = $statement->fetchAll();

       //@JA - Get the list of all the apn tokens we need to send the message to.
       foreach($mobiletokens as $tokenobject){
           $deviceTokens[] = $tokenobject["apntoken"];
           echo $tokenobject["apntoken"]."\n";
       }

Answer 2

您可以使用用querybuilder創建的子選擇作為示例：

public function selectNewAppToken($userId)
{
    // get an ExpressionBuilder instance, so that you
    $expr = $this->_em->getExpressionBuilder();

    // create a subquery in order to take all address records for a specified user id
    $sub = $this->_em->createQueryBuilder()
        ->select('a')
        ->from('AppBundle:MobileTokens', 'a')
        ->where('a.user = dm.id')
        ->andWhere('a.deviceid = dm.deviceid')
        ->andWhere($expr->gte('a.created','dm.created'));


    $qb = $this->_em->createQueryBuilder()
        ->select('dm')
        ->from('AppBundle:MobileTokens', 'dm')
        ->where($expr->not($expr->exists($sub->getDQL())))
        ->andWhere('dm.user = :user_id')
        ->setParameter('user_id', $userId);

    return $qb->getQuery()->getResult();
}