[英]Change returned value in SQL query
我正在使用實時查看程序來進行SQL查詢(並讓我編輯代碼的一部分)
目前代碼是:
SELECT
[LogonName] AS [Logon name],
[LogonExtension] AS [Logon extension],
[VoiceReady] AS [Ready for Voice],
[CallState] AS [Call state]
FROM
[AgentPerformance]
WHERE
(AgentID IN (1, 2, 3))
返回:
現在我的問題是,有沒有辦法改變返回的“呼叫狀態”值,讓我們說忙,免費,處理等...(有3個不同的值)。
我試過例如:
SELECT
[LogonName] AS [Logon name],
[LogonExtension] AS [Logon extension],
[VoiceReady] AS [Ready for Voice],
[CallState] AS [Call state]
FROM
[AgentPerformance]
WHERE
(AgentID IN (1, 2, 3))
SELECT
CASE
WHEN CallState = 0 THEN 'No'
WHEN CallState = 1 THEN 'Yes
ELSE 'Maybe'
END AS kakaduu
FROM
AgentPerformance
但這對我不起作用。
您的CASE
表達式需要與其他列一起位於SELECT
列表中。 第二個SELECT
在您的示例中是不正確的語法。
所以,試試這個:
SELECT [LogonName] AS [Logon name], [LogonExtension] AS [Logon extension], [VoiceReady] AS [Ready for Voice], [CallState] AS [Call state],
CASE
WHEN CallState = 0 then 'No'
WHEN CallState = 1 then 'Yes'
ELSE 'Maybe'
END
AS kakaduu
FROM [AgentPerformance]
WHERE AgentID IN (1, 2, 3)
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