簡體   English   中英

更改SQL查詢中的返回值

[英]Change returned value in SQL query

我正在使用實時查看程序來進行SQL查詢(並讓我編輯代碼的一部分)

目前代碼是:

SELECT 
    [LogonName] AS [Logon name], 
    [LogonExtension] AS [Logon extension], 
    [VoiceReady] AS [Ready for Voice], 
    [CallState] AS [Call state]
FROM 
    [AgentPerformance]
WHERE 
    (AgentID IN (1, 2, 3))

返回:

在此輸入圖像描述

現在我的問題是,有沒有辦法改變返回的“呼叫狀態”值,讓我們說忙,免費,處理等...(有3個不同的值)。

我試過例如:

SELECT 
    [LogonName] AS [Logon name], 
    [LogonExtension] AS [Logon extension], 
    [VoiceReady] AS [Ready for Voice], 
    [CallState] AS [Call state]
FROM
    [AgentPerformance]
WHERE 
    (AgentID IN (1, 2, 3))

SELECT 
    CASE 
       WHEN CallState = 0 THEN 'No'
       WHEN CallState = 1 THEN 'Yes
       ELSE 'Maybe'
    END AS kakaduu
FROM 
    AgentPerformance

但這對我不起作用。

您的CASE表達式需要與其他列一起位於SELECT列表中。 第二個SELECT在您的示例中是不正確的語法。

所以,試試這個:

SELECT [LogonName] AS [Logon name], [LogonExtension] AS [Logon extension], [VoiceReady] AS [Ready for Voice], [CallState] AS [Call state],
CASE 
    WHEN CallState = 0 then 'No'
    WHEN CallState = 1 then 'Yes'
    ELSE 'Maybe'
END
AS kakaduu
FROM [AgentPerformance]
WHERE   AgentID IN (1, 2, 3) 

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM