python sqlite3 插入列表

Question

我有一個 python 腳本，它應該將一個列表插入到 sqlite 表中。 看來我的插入語句不起作用。

links = ['a', 'b', 'c']

conn = sqlite3.connect('example.db')

#create a data structure
c = conn.cursor()

#Create table
c.execute('''Create TABLE if not exists server("sites")''')

#Insert links into table
def data_entry():
    sites = links
    c.execute("INSERT INTO server(sites) VALUES(?)", (sites))
    conn.commit()

#query database
c.execute("SELECT * FROM server")
rows = c.fetchall()
for row in rows:
    print(row)

conn.close

我在命令行檢查了數據庫，但“服務器”表為空：

C:\App\sqlite\sqlite_databases>sqlite3
SQLite version 3.17.0 2017-02-13 16:02:40
Enter ".help" for usage hints.
Connected to a transient in-memory database.
Use ".open FILENAME" to reopen on a persistent database.
sqlite> .tables
server
sqlite> SELECT * FROM server
...> ;
sqlite>

所以看起來實際上並沒有插入列表。

Answer 1

遍歷list_並為每個項目執行INSERT 。 並調用data_entry()實際插入數據。

import sqlite3

list_ = ['a', 'b', 'c']

#create a data structure
conn = sqlite3.connect('example.db')
c = conn.cursor()

#Create table
c.execute('''Create TABLE if not exists server("sites")''')

#Insert links into table
def data_entry():
    for item in list_:
        c.execute("INSERT INTO server(sites) VALUES(?)", (item))
    conn.commit()

data_entry()  # ==> call the function

#query database
c.execute("SELECT * FROM server")
rows = c.fetchall()
for row in rows:
    print(row)

conn.close()

Answer 2

制作一個二維列表並使用executemany() 。

links = ['a', 'b', 'c']

conn = sqlite3.connect('example.db')

#create a data structure
c = conn.cursor()

#Create table
c.execute('''Create TABLE if not exists server("sites")''')

#Insert links into table
def data_entry(links):
    sites = [(s,) for s in links]
    c.executemany("INSERT INTO server(sites) VALUES(?)", sites)
    conn.commit()

data_entry(links)

#query database
c.execute("SELECT * FROM server")
rows = c.fetchall()
for row in rows:
    print(row)

conn.close