從多對多關系中獲取數據

Question

我有以下型號：

class Speaker(models.Model):
    id_speaker = models.UUIDField(primary_key=True)
    name = models.TextField()

class Session(models.Model):
    id_session = models.UUIDField(primary_key=True)
    name = models.TextField()
    speakers = models.ManyToManyField(Speaker)

當查詢Session.objects.all() ，我得到了下一個示例數據：

{
  "id_session": "UUID",
  "name": "Example name",
  "speakers": [
    {
      "id_speaker": "UUID",
      "name": "John Doe"
    }
  ]
}

如您所見，我有會議發言人列表，現在的問題是，如何獲得發言人會議，這是我想要的一個示例：

{
    "id_speaker": "UUID",
    "name": "John Doe",
    "sessions": [
        {
            "id_session": "UUID",
            "name": "Example name"
        }
    ]
}

如果您想知道我是否使用django-rest-framework，答案為是。

Answer 1

can您不能更改模型的結構嗎？

class Session(models.Model):
    id_session = models.UUIDField(primary_key=True)
    name = models.TextField()


class Speaker(models.Model):
    id_speaker = models.UUIDField(primary_key=True)
    name = models.TextField()
    session = models.ManyToManyField(Session)

不知道我是否正確理解您的問題。

Answer 2

嘗試related_name Django相關名稱

注意related_name在ManyToManyField kwarg

class Speaker(models.Model):
    id_speaker = models.UUIDField(primary_key=True)
    name = models.TextField()

class Session(models.Model):
    id_session = models.UUIDField(primary_key=True)
    name = models.TextField()
    speakers = models.ManyToManyField(Speaker, related_name='sessions')

然后，您可以從發言人對象獲得所有會話

some_speaker.sessions.all()  #Returns sessions