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[英]Angular JS, how to pass URL parameters to $resouce in angularJS?
[英]How to pass angular JS value in URL as parameters
我有以下鏈接
<a href="entity-details.html?id='{{ x.community_id }}&community_society_id={{x.community_society_id}}">View</a>
我希望將x.community_id和x.community_society_id值傳遞給控制器,然后再獲取數據。
var app = angular.module('EntityApp', []);
app.controller('EntityAppCntroller', function($scope, $http, $location) {
var myParamtr = location.search.split('id=')[1] ? location.search.split('id=')[1] : 'myDefaultValue';
alert(myParamtr);
$http.get('apartment/community/details/list/'+ myParam).then(function(response) {
$scope.myData = response.data.list;
});
});
您需要使用ng-href,以便可以將值內置到鏈接中。 Lke @tanmay在評論中說。
<a ng-href="entity-details.html?id={{ x.community_id }}&community_society_id={{x.community_society_id}}">View</a>
更改控制器以正確解析網址。
var app = angular.module('EntityApp', []);
app.controller('EntityAppCntroller', function($scope, $http, $location) {
var getJsonFromUrl = function(url) {
console.log(url);
var query = url.substr(1);
var result = {};
query.split("&").forEach(function(part) {
var item = part.split("=");
result[item[0]] = decodeURIComponent(item[1]);
});
return result;
};
var queryParams = getJsonFromUrl(location.search);
var myParamtr = queryParams.id ? queryParams.id : 'myDefaultValue';
alert(myParamtr);
$http.get('apartment/community/details/list/'+ myParam).then(function(response) {
$scope.myData = response.data.list;
});
});
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