MySQL連接兩個表的總和，其中和分組依據

Question

我有以下結構的兩個表：

sales
 |date       |time     | name   | total |
 |2017-04-01 |10:23:59 | aaa    |  100  |
 |2017-04-01 |10:23:59 | aaa    |  150  |
 |2017-04-01 |11:33:30 | bbb    |  200  |
 |2017-04-01 |11:33:30 | bbb    |  120  |
 |2017-04-02 |10:50:59 | aaa    |  70   |
 |2017-04-02 |10:30:59 | bbb    |  35   |

payment
 |date       |time     | name   | amount |
 |2017-04-01 |10:23:59 | aaa    |  300   |
 |2017-04-01 |11:33:30 | bbb    |  400   |
 |2017-04-02 |10:50:59 | aaa    |  425   |
 |2017-04-02 |10:30:59 | bbb    |  600   |

條款

1. sales.time =付款時間
2. 日期= 2017-04-01
3. 總計（銷售額。總計）和總計（付款。金額）
4. 按時間分組

我想要這個結果

 |date       |time     | name   | sum(total) | sum(amount)|
 |2017-04-01 |13:23:59 | aaa    |    250     |    300     |
 |2017-04-01 |12:33:30 | bbb    |    320     |    400     |

表結構

CREATE TABLE `payment` (`id` int(5) NOT NULL,`date` date NOT NULL,`time` time NOT NULL,`name` varchar(10) NOT NULL,`amount` varchar(10) NOT NULL) ENGINE=InnoDB DEFAULT CHARSET=latin1 ROW_FORMAT=COMPACT;
INSERT INTO `payment` (`id`, `date`, `time`, `name`, `amount`) VALUES(3, '2017-04-01', '10:23:59', 'aaa', '300'),(4, '2017-04-01', '11:33:30', 'bbb', '400'),(5, '2017-04-02', '10:50:59', 'aaa', '425'),(6, '2017-04-02', '10:30:59', 'bbb', '600');
CREATE TABLE `sales` ( `id` int(5) NOT NULL,`date` date NOT NULL,`time` time NOT NULL,`name` varchar(10) NOT NULL,`total` int(10) NOT NULL) ENGINE=InnoDB DEFAULT CHARSET=latin1;
INSERT INTO `sales` (`id`, `date`, `time`, `name`, `total`) VALUES(1, '2017-04-01', '10:23:59', 'aaa', 100),(2, '2017-04-01', '10:23:59', 'aaa', 150),(3, '2017-04-01', '11:33:30', 'bbb', 200),(4, '2017-04-01', '11:33:30', 'bbb', 120),(5, '2017-04-02', '10:50:59', 'aaa', 70),(6, '2017-04-02', '10:50:59', 'bbb', 35);
ALTER TABLE `payment` ADD PRIMARY KEY (`id`);
ALTER TABLE `sales` ADD PRIMARY KEY (`id`);
ALTER TABLE `payment` MODIFY `id` int(5) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=7;
ALTER TABLE `sales` MODIFY `id` int(5) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=7;

詢問

SELECT sales.time,sales.name,  
SUM(sales.total),SUM(payment.amount)
FROM sales,payment  
WHERE sales.time=payment.time
and sales.date like '2017-04-01%'
GROUP BY sales.time
ORDER BY sales.time;

結果是

10:23:59    aaa 250 600
11:33:30    bbb 320 800

Answer 1

您正在將付款金額乘以銷售記錄數，因為您在將金額相加之前將所有付款記錄與所有銷售記錄結合在一起。

首先聚集，然后才加入。

如果每個日期，時間和名稱始終只能有一個付款記錄：

select p.name, p.time, p.name, s.sales_total, p.amount
from payments p
join
(
  select date, time, name, sum(total) as total
  from sales
  group by date, time, name
) s
 on s.date = p.date and s.time = p.time and s.name = p.name
where p.date = date '2017-04-01';

除此以外：

select p.name, p.time, p.name, s.total, p.amount
(
  select date, time, name, sum(amount) as amount
  from payments
  group by date, time, name
) p
join
(
  select date, time, name, sum(total) as total
  from sales
  group by date, time, name
) s
 on s.date = p.date and s.time = p.time and s.name = p.name
where p.date = date '2017-04-01';