[英]How to display postgresql search results using PHP
問題
您好,我正在創建一個搜索功能,允許用戶搜索特定的電子號碼,看看它是否來自動物,基本上看它是否是素食主義者。 我已經成功地在我的網站上使用PHP連接到數據庫。
編碼
在頁面頂部:
<?php
// Connecting, selecting database
$dbconn = pg_connect("host=***** port=*****
dbname=**** user=**** password=*****")
or die('Could not connect: ' . pg_last_error());
//collect
if(isset($_POST['search'])) {
$searchq = $_POST['search'];
// Performing SQL query
$query = 'SELECT vegan FROM enumbers WHERE code = searchq';
}
?>
搜索欄:
<div id="tablebox">
<!-- Search bar -->
<p>Is It Vegan?</p>
<form name="form1" method="post" action="searchEnumbers.php">
<input name="search" type="text" size="30" maxlength="5" />
<input name="submit" type="submit" value="Search" />
</form>
</div>
我現在如何顯示已搜索的“純素”結果? 我不確定如何打印結果。
更新
enumbers表中的列名是:'code','name','type'和'vegan'。
<?php
// Connecting, selecting database
$dbconn = pg_connect("host=db.dcs.aber.ac.uk port=5432
dbname=cs399030_16_17 user=sec17 password=Liverpool2112")
or die('Could not connect: ' . pg_last_error());
//collect
if(isset($_POST['search'])) {
$searchq = $_POST['search'];
// Performing SQL query
$pg_query = 'SELECT vegan FROM enumbers WHERE code = '.$searchq;
$result = pg_query($query);
foreach($result as $r){ //If you have multiple records or $result
echo "<p> Your ".$r->params." or ".$r['params']." here </p>"; //for instance
}
}
?>
你應該有類似的東西:
<?php
// Connecting, selecting database
$dbconn = pg_connect("host=**** port=****
dbname=**** user=**** password=****")
or die('Could not connect: ' . pg_last_error());
//collect
if(isset($_POST['search'])) {
$searchq = $_POST['search'];
// Performing SQL query
$query = 'SELECT vegan FROM enumbers WHERE code = '.$searchq;
// make the query with: pg_query
// $result = pg_query($query);
foreach($result as $r){ //If you have multiple records or $result
echo "<p> Your ".$r->params." or ".$r['params']." here </p>"; //for instance
}
//you could use: var_dump(pg_fetch_all($result));
}
?>
<!-- If you want to show always the form. If not, put inside the else -->
<div id="tablebox">
<!-- Search bar -->
<p>Is It Vegan?</p>
<form name="form1" method="post" action="searchEnumbers.php">
<input name="search" type="text" size="30" maxlength="5" />
<input name="submit" type="submit" value="Search" />
</form>
</div>
請注意,這not the best
方法(您可以使用AJAX,以及不同的頁面,以便現在刷新頁面),或其他方式。 但這可以按照你想要的方式工作。
查看PHP的官方文檔: http : //php.net/manual/kr/function.pg-connect.php
希望能幫助到你!
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