[英]How can I specify a mainClass in build.sbt that resides in another module?
由於某種原因,我們的項目進行了重組,將主類放入了另一個模塊中
我在mainClass
指定了mainClass
,如下所示,但仍然出現未找到類錯誤:
mainClass in Compile := Some("com.so.questions.sbt.Main")
但是,這肯定會失敗,因為它將在src
文件夾中查找Main類。 但是,此模塊位於src
(的兄弟)之外:
MyScalaProject
+-MyModule
|+-src
| +-com.so.questions.sbt
| +-Main
|+-build.sbt <-- build.sbt specific to this module, currently blank
+-src
| +-<other folders>
+-build.sbt <-- build.sbt currently housing all config
如何更改build.sbt
的項目范圍以查找並正確加載主類?
也就是說,是否可以在頂級sbt run
並通過這種結構找到主類?
它應該工作。
根據我的理解, mainClass
的FQCN規范應獨立於位置。
真正想到的問題是如何加載子模塊。 以下是一些sbt定義,這些定義應有助於您指出正確的方向(將<>
標記替換為您自己的項目ID):
// Define a submodule ref to be able to include it as a dependency
lazy val subModuleRef = ProjectRef(file("MyModule"),<MyModule SBT NAME>)
// Define a submodule project to be able to orchestrate it's build
lazy val subModule = Project(
id = <MyModule SBT NAME>,
base = file("MyModule"),
).addSbtFiles(file("build.sbt"))
// Define the top-level project, depending and subModule Ref for code
// inclusion and aggregating the subModule for build orchestration
lazy val scalaProject = Project(
id = <MyScalaProject NAME>,
base = file("."),
aggregate = Seq(subModule),
settings = commonSettings
).dependsOn(subModuleRef).
假設您有MyModule
模塊/文件夾,其中包含主類和其他名為MyCoreModule
模塊(僅用於說明整個build.sbt):
// any stuff that you want to share between modules
lazy val commonSettings = Seq(
scalaVersion := "2.12.8",
version := "1.0-SNAPSHOT"
)
lazy val root = (project in file("."))
.settings(commonSettings: _*)
.settings(
name := "parent-module"
)
.aggregate(core, app)
.dependsOn(app) // <-- here is the config that will allow you to run "sbt run" from the root project
lazy val core = project.in(file("MyCoreModule"))
.settings(commonSettings: _*)
.settings(
name := "core"
)
lazy val app = project.in(file("MyModule"))
.dependsOn(core)
.settings(commonSettings: _*)
.settings(
name := "app"
)
// define your mainClass from the "app" module
mainClass in Compile := (mainClass in Compile in app).value
順便說一句, sbt.version=1.2.7
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