Python Int對​​象不可調用

Question

請幫忙！ 我不明白這里的錯誤。 當我鍵入0、1或2以外的數字時，為什么會出現錯誤消息：“'int'對象不可調用”？ 相反，它應該打印“您輸入的數字不正確，請重試”，然后返回詢問問題。

第二個問題：另外，如何以某種方式更改代碼，即使我鍵入字母字符，也不會給我“值錯誤”並繼續重新提出問題？ 謝謝！

def player_action():        
    player_action = int(input("Enter 0 to stay, 1 to go Up, or 2 to go Down: "))

    if player_action == 0:
        print ("Thank You, you chose to stay")


    if player_action == 1:
        print ("Thank You, you chose to go up")

    if player_action == 2:
        print ("Thank You, you chose to go down")

    else:
        print ("You have entered an incorrect number, please try again")
        player_action()

player_action()

Answer 1

佩德羅（Pedro）已回答您問題的第一個答案，但至於第二個答案，請嘗試try語句可以解決此問題：

編輯：是的，對不起，我把它弄亂了……有更好的答案，但我認為我應該花點時間解決這個問題

def player_action():
    try:
        player_action_input = int(input("Enter 0 to stay, 1 to go Up, or 2 to go Down: "))
    except ValueError:
        print("Non valid value") # or somehting akin
        player_action()
    if player_action_input == 0:
        print ("Thank You, you chose to stay")
    elif player_action_input == 1:
        print ("Thank You, you chose to go up")
    elif player_action_input == 2:
        print ("Thank You, you chose to go down")
    else:
        print ("You have entered an incorrect number, please try again")
            player_action()

player_action()

Answer 2

您應該按照@Pedro Lobito的建議更改變量名稱，按照@Craig的建議使用while循環，還可以包括try...except語句，但不能采用@ polarisfox64的方式（因為他將其放在錯誤的位置）位置。

這是完整版本供您參考：

def player_action():    
    while True:   
        try:
            user_input = int(input("Enter 0 to stay, 1 to go Up, or 2 to go Down: "))
        except ValueError:
            print('not a number')
            continue

        if user_input == 0:
            print ("Thank You, you chose to stay")          

        if user_input == 1:
            print ("Thank You, you chose to go up")

        if user_input == 2:
            print ("Thank You, you chose to go down")

        else:
            print ("You have entered an incorrect number, please try again")
            continue
        break

player_action()

Answer 3

只需將變量名稱player_action更改為函數的差異名稱即可，即：

def player_action():
    user_input = int(input("Enter 0 to stay, 1 to go Up, or 2 to go Down: "))
    if user_input == 0:
        print ("Thank You, you chose to stay")
    elif user_input == 1:
        print ("Thank You, you chose to go up")
    elif user_input == 2:
        print ("Thank You, you chose to go down")
    else:
        print ("You have entered an incorrect number, please try again")
        player_action()

player_action()