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[英]Countdown to every saturday in Javascript, then open a 3 hour bracket?
[英]Javascript countdown not repeating every saturday
我的倒數應該在每個星期六的晚上8點(gmt + 2)重復,但是一旦到達晚上8點,倒數就會停留在EXPIRED上。 我不明白為什么,有人知道這個問題嗎?
提前感謝您的幫助和感謝。
function nextSaturday() {
var d = new Date();
console.log(d.getDay());
if (d.getDay() == 7 && d.getHours() < 20){
d.setHours(20);
d.setMinutes(0);
d.setSeconds(0);
return d;
}
switch (d.getDay()) {
case 0: d.setDate(d.getDate() + 6);
break;
case 1: d.setDate(d.getDate() + 5);
break;
case 2: d.setDate(d.getDate() + 4);
break;
case 3: d.setDate(d.getDate() + 3);
break;
case 4: d.setDate(d.getDate() + 2);
break;
case 5: d.setDate(d.getDate() + 1);
break;
case 6: d.setDate(d.getDate() + 0);
break;
}
d.setHours(20);
d.setMinutes(0);
d.setSeconds(0);
return d;
}
var end = nextSaturday();
var _second = 1000;
var _minute = _second * 60;
var _hour = _minute * 60;
var _day = _hour * 24;
var timer;
function showRemaining() {
var now = new Date();
var distance = end - now;
if (distance < 0) {
clearInterval(timer);
document.getElementById("countdown").innerHTML = "EXPIRED!";
return;
}
var days = Math.floor(distance / _day);
var hours = Math.floor((distance % _day) / _hour);
var minutes = Math.floor((distance % _hour) / _minute);
var seconds = Math.floor((distance % _minute) / _second);
document.getElementById("countdown").innerHTML = "Countdown ends in: ";
document.getElementById("countdown").innerHTML += days + " days ";
document.getElementById("countdown").innerHTML += hours + " hours ";
document.getElementById("countdown").innerHTML += minutes + " minutes and ";
document.getElementById("countdown").innerHTML += seconds + " seconds left";
}
showRemaining();
timer = setInterval(showRemaining, 1000);
您將盡早從此功能返回。
if(d.getDay() == 7 && d.getHours() < 20) {
d.setHours(20);
d.setMinutes(0);
d.setSeconds(0);
return d; //right here you are exiting your loop at 8:00 (20 hours)
}
return d;
終止函數的執行並返回d
的值
你已經d
這個點設置到這個星期六,你希望它是下周六,所以你需要補充一點:
d.setDate(d.getDate() + 7);
在您返回d
之前。
說明:
上面的if語句基本上是說:“如果在星期六晚上8:00之后,請將d設置為星期六晚上8:00”。 當代碼開始將日期重置為下一個星期六時,您的代碼將在星期日的12:00 am重新開始工作,如果您恰好像在一周中所有其他天一樣都是星期六,則您只是忘記了增加日期。
該代碼完全應該是:
if(d.getDay() == 7) { //note: I've also updated this line to account for changes in hours
d.setHours(20);
d.setMinutes(0);
d.setSeconds(0);
if(d.getHours() >= 20)
d.setDate(d.getDate() + 7);
return d;
}
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