簡體   English   中英

內部聯接

[英]Inner Join

$query4 = mysql_query("SELECT * FROM comments WHERE content_id = '$id' AND     content = 'thread'
                  INNER JOIN users ON comments.poster = users.id
                  ORDER BY comments.date ASC");
while ($comment = mysql_fetch_array($query4)) {
}

所有的表和列都存在,我連接到數據庫,但它仍然給我:

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in thread.php on line 63

我在這里做錯了什么?

提前致謝。

您的連接語法錯誤。 嘗試:

SELECT *
FROM comments
INNER JOIN users ON comments.pooster = users.id
WHERE comments.content_id = '$id'
ORDER BY comments.date ASC

暫無
暫無

聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.

 
粵ICP備18138465號  © 2020-2024 STACKOOM.COM