[英]JSON response from php on AJAX call
我正在從 Java 腳本執行 ajax 調用,並且我試圖從 php 獲取 json 響應,如果我將 dataType 設置為 JSON,如果沒有執行成功塊,則會執行 ajax 錯誤塊,如果我嘗試 console.log,則不指定 dataType成功塊中的響應我什么也沒得到
JS
let CurrentDate = Date();
console.log(CurrentDate);
jsonObject = {
'TrackName' : 'Material Science',
'TrackDesc' : 'Test Text Test Text Test Text Test Text Test Text Test Text Test Text ',
'Timestamp' : CurrentDate
}
console.log(jsonObject);
$.ajax({
type:'post',
url:'../../../../PHP/adminScripts/addNewTrack.php',
contentType: "application/json",
data: {trackDetails:jsonObject},
dataType: "json",
success: function(response) {
console.log('SUCCESS BLOCK');
console.log(response);
},
error: function(response) {
console.log('ERROR BLOCK');
console.log(response);
}
});
PHP
<?php
header('Content-type: application/json');
include('../connection.php');
if($_POST) {
$obj = $_POST['trackDetails'];
$TrackName = mysql_real_escape_string($obj['TrackName']);
$TrackDesc = mysql_real_escape_string($obj['TrackDesc']);
$TrackAdderID = 'Admin '; //$_SESSION["userID"];
$Timestamp = mysql_real_escape_string($obj['Timestamp']);
$response_array['status'] = 'status123';
echo json_encode($response_array);
請幫我弄清楚如何在 PHP 中獲得對 ajax 調用的 json 響應
contentType: "application/json",
JS文件:
let CurrentDate = Date();
jsonObject = {
'TrackName' : 'Material Science',
'TrackDesc' : 'Test Text Test Text Test Text Test Text Test Text Test Text Test Text ',
'Timestamp' : CurrentDate
}
$.ajax({
type:'post',
url:'addNewTrack.php',
data: {trackDetails:jsonObject},
dataType: "json",
success: function(response) {
console.log('SUCCESS BLOCK');
console.log(response);
},
error: function(response) {
console.log('ERROR BLOCK');
console.log(response);
}
});
PHP文件:
<?php
header('Content-type: application/json');
include('../connection.php');
if($_POST) {
$obj = $_POST['trackDetails'];
$TrackName = mysql_real_escape_string($obj['TrackName']);
$TrackDesc = mysql_real_escape_string($obj['TrackDesc']);
$TrackAdderID = 'Admin '; //$_SESSION["userID"];
$Timestamp = mysql_real_escape_string($obj['Timestamp']);
$response_array['status'] = 'status123';
echo json_encode($response_array);
}
?>
從您的 JS 代碼中刪除contentType: "application/json"
,並在 PHP 文件中正確關閉大括號,它會正常工作。
您可以使用 json_encode() 函數將 PHP 數組轉換為 JSON 格式並作為響應返回。 發送 AJAX 請求時設置 dataType: 'JSON'。
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