[英]Why does this not work? (C++)
我有這段代碼來計算形狀的面積。 我不明白為什么我在第44行的“類Triangle :: Triangle(double s1,double s2,double s3)”上收到錯誤“ expected unqualified id before'double'”和“ expected(before double”)的錯誤:Polygon(s1, s2,s3,0.0){}。”非常感謝您的幫助。在此先感謝您。
#include "Polygon.h"
#include <iostream>
#include <cmath>
using namespace std;
//Polygon constructor
Polygon :: Polygon(double side1, double side2, double side3, double side4)
{
s1 = side1;
s2 = side2;
s3 = side3;
s4 = side4;
}
//get area method
double Polygon :: getArea()
{
float length, width, area;
if (s1 == s2)
{
length = s1;
width = s3;
}
else if (s1 == s3)
{
length = s1;
width = s2;
}
else if (s1 == s4)
{
length = s1;
width = s3;
}
area = length * width;
return area;
}
//Triangle class
class Triangle :: Triangle(double s1, double s2, double s3) : Polygon(s1, s2, s3, 0.0) {}
double Triangle :: getArea()
{
float s, area;
s = (s1 + s2 + s3)/2;
area = sqrt(s * (s - s1) * (s - s2) * (s - s3));
return area;
}
您需要在此處刪除單詞class
:
class Triangle :: Triangle
當然,您需要確保在此之前聲明了class Triangle
。
使用以下代碼片段。
#include "Polygon.h"
#include <iostream>
#include <cmath>
using namespace std;
//Polygon constructor
Polygon :: Polygon(double side1, double side2, double side3, double side4)
{
s1 = side1;
s2 = side2;
s3 = side3;
s4 = side4;
}
//get area method
double Polygon :: getArea()
{
float length, width, area;
if (s1 == s2)
{
length = s1;
width = s3;
}
else if (s1 == s3)
{
length = s1;
width = s2;
}
else if (s1 == s4)
{
length = s1;
width = s3;
}
area = length * width;
return area;
}
//Triangle class
Triangle :: Triangle(double s1, double s2, double s3) : Polygon(s1, s2, s3, 0.0) {}
double Triangle :: getArea()
{
float s, area;
s = (s1 + s2 + s3)/2;
area = sqrt(s * (s - s1) * (s - s2) * (s - s3));
return area;
}
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