[英]Make all tables in database UNLOGGED
我想通過使所有表UNLOGGED
來減少本地測試執行時間。 我想編寫 sql 腳本,它將在所有轉換后運行並使它們成為UNLOGGED
。 但我發現問題 - 表與FK
相互關聯,因此如果 postgresql 與尚未UNLOGGED
其他表相關,則禁止 make table UNLOGGED
(通過ALTER
)。
有沒有更好的方法然后以正確的順序列出所有ALTER
- 我有超過 150 個表? 例如,將其應用於數據庫級別。
恐怕你必須以正確的順序改變它們。 您可以選擇https://www.postgresql.org/docs/current/static/catalog-pg-constraint.html並首先循環引用表,然后更改其余部分:
begin;
do
$$
declare
_r record;
_t text;
begin
for _r in (
select relname,conrelid
from pg_constraint
join pg_class c on c.oid = conrelid
where confkey is not null
order by conrelid desc
-- Order by oid with logic that you should start from latest added objects to earliest - of course it does not garantee anything
) loop
_t := format('alter table %I set unlogged',_r.relname);
raise info '%',_t;
execute _t;
end loop;
for _r in (select tablename from pg_tables where tablename like 's%' and schemaname = 'public') loop
_t := format('alter table %I set unlogged',_r.tablename);
raise info '%',_t;
execute _t;
end loop;
end;
$$
;
rollback;
如果您有遞歸 FK,它無論如何都會失敗:
t=# create table s134(i int primary key, e int);
CREATE TABLE
t=# create table s135(i int references s134(i), e int primary key);
CREATE TABLE
t=# alter table s134 add constraint c1 foreign key (e) references s135(e);
ALTER TABLE
t=# alter table s134 set unlogged;
ERROR: could not change table "s134" to unlogged because it references logged table "s135"
t=# alter table s135 set unlogged;
ERROR: could not change table "s135" to unlogged because it references logged table "s134"
但我相信你不會以任何方式實現這一目標。
也不要忘記在不干凈的關閉或失敗后,未記錄的表將被截斷。
最后你說“在所有轉換之后”——如果你創建、轉換等,也許你應該創建它們而不被記錄?..
我會刪除並重新創建所有外鍵。 您可以自動執行此操作。
以下查詢將為所有外鍵生成必要的 DDL 語句。 您需要將其輸出保存到一個文件中,稍后您可以使用該文件恢復所有外鍵。
select format('alter table %I.%I add constraint %I ', ns.nspname, tb.relname, conname)||
pg_get_constraintdef(c.oid, true)||';' as ddl
from pg_constraint c
join pg_class tb on tb.oid = c.conrelid
join pg_namespace ns on ns.oid = tb.relnamespace
where ns.nspname not in ('pg_catalog', 'information_schema')
and ns.nspname not like 'pg_temp%'
and c.contype in ('f')
然后生成一個腳本來刪除所有約束:
select format('alter table %I.%I drop constraint %I cascade;', ns.nspname, tb.relname, c.conname) as ddl
from pg_constraint c
join pg_class tb on tb.oid = c.conrelid
join pg_namespace ns on ns.oid = tb.relnamespace
where ns.nspname not in ('pg_catalog', 'information_schema')
and ns.nspname not like 'pg_temp%'
and c.contype in ('f');
當然,您必須在刪除它們之前運行查詢以生成 FK ;)
我對接受的答案有困難,因為它依賴於啟發式(可能不適用)來獲得正確的排序。 我使用(有點冗長)遞歸查詢重新設計了建議的答案,該查詢允許獲得所需的確切排序。 我沒有用遞歸 FK 對其進行測試,我懷疑遞歸查詢不會終止。 請注意,我已將查詢限制為應用於public
架構中的表,請進行修改以滿足您自己的需要。
注銷所有表:
do
$$
declare
_r record;
_t text;
begin
for _r in (
WITH RECURSIVE constraints AS (
SELECT
tc.table_schema
, tc.table_name
, kcu.column_name
, ccu.table_name AS foreign_table_name
FROM
information_schema.table_constraints AS tc
LEFT OUTER JOIN information_schema.key_column_usage AS kcu
ON tc.constraint_name = kcu.constraint_name
AND tc.table_schema = kcu.table_schema
LEFT OUTER JOIN information_schema.constraint_column_usage AS ccu
ON ccu.constraint_name = tc.constraint_name
AND ccu.table_schema = tc.table_schema
WHERE (tc.constraint_type IS NULL OR tc.constraint_type = 'FOREIGN KEY'))
, tables_and_constraints AS (
SELECT
t.table_schema
, t.table_name
, c.foreign_table_name
FROM information_schema.tables AS t
LEFT JOIN constraints AS c USING (table_name)
WHERE t.table_type <> 'VIEW')
, dependent_table_constraints AS (
SELECT tc.table_schema
, tc.table_name
, tc.foreign_table_name
, 0 AS depth
FROM tables_and_constraints AS tc
WHERE foreign_table_name IS NULL
UNION
SELECT tc.table_schema
, tc.table_name
, tc.foreign_table_name
, dtc.depth + 1
FROM tables_and_constraints AS tc
INNER JOIN dependent_table_constraints AS dtc ON tc.foreign_table_name = dtc.table_name
) SELECT table_name, max(depth) as depth FROM dependent_table_constraints
WHERE table_schema = 'public'
GROUP BY table_name
ORDER BY depth DESC
) loop
_t := format('ALTER TABLE %I SET UNLOGGED',_r.table_name);
raise info '%',_t;
execute _t;
end loop;
end;
$$
;
重新記錄所有表:
do
$$
declare
_r record;
_t text;
begin
for _r in (
WITH RECURSIVE constraints AS (
SELECT
tc.table_schema
, tc.table_name
, kcu.column_name
, ccu.table_name AS foreign_table_name
FROM
information_schema.table_constraints AS tc
LEFT OUTER JOIN information_schema.key_column_usage AS kcu
ON tc.constraint_name = kcu.constraint_name
AND tc.table_schema = kcu.table_schema
LEFT OUTER JOIN information_schema.constraint_column_usage AS ccu
ON ccu.constraint_name = tc.constraint_name
AND ccu.table_schema = tc.table_schema
WHERE (tc.constraint_type IS NULL OR tc.constraint_type = 'FOREIGN KEY'))
, tables_and_constraints AS (
SELECT
t.table_schema
, t.table_name
, c.foreign_table_name
FROM information_schema.tables AS t
LEFT JOIN constraints AS c USING (table_name)
WHERE t.table_type <> 'VIEW')
, dependent_table_constraints AS (
SELECT tc.table_schema
, tc.table_name
, tc.foreign_table_name
, 0 AS depth
FROM tables_and_constraints AS tc
WHERE foreign_table_name IS NULL
UNION
SELECT tc.table_schema
, tc.table_name
, tc.foreign_table_name
, dtc.depth + 1
FROM tables_and_constraints AS tc
INNER JOIN dependent_table_constraints AS dtc ON tc.foreign_table_name = dtc.table_name
) SELECT table_name, max(depth) as depth FROM dependent_table_constraints
WHERE table_schema = 'public'
GROUP BY table_name
ORDER BY depth ASC
) loop
_t := format('ALTER TABLE %I SET LOGGED',_r.table_name);
raise info '%',_t;
execute _t;
end loop;
end;
$$
;
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.