將鍵值傳遞到另一個具有不同長度的數組

Question

嗨，我有兩個數組，里面有對象。 我正在嘗試將title屬性的哈希值傳遞給也具有標題鍵-值對但不具有哈希值（這是一個空字符串）的另一個數組的對象。

訣竅是數組未排序，並且它們具有不同的長度。

這是我的代碼：

 var res = [ [{ title: "time goes by", searchhash: "" }, { title: "gta vice city", searchhash: "" }, { title: "miami beach", searchhash: "" } ], [{ title: "miami beach", search_hash: "12456" }, { title: "time goes by", search_hash: "98765" } ] ] for (var i = 0; i < res[0].length; i++) { if (res[0][i].searchhash === "") { titlePass(res[0][i].title) res[0][i].searchhash = function hashPass(p) { console.log(p); i += 1 } } } function titlePass(t) { //Here I'm getting the titles (t) res[1].forEach((obj) => { if (t === obj.title) { hashPass(obj["search_hash"]) } }) } 

但是我得到的不是hashPass函數。 我知道我可以訪問forPass循環中的hashPass函數的那些值，但是我想讓這些值在for循環內傳遞，以將其分配給searchhash屬性...

Answer 1

你是這個意思嗎

 var res = [ [{ title: "time goes by", searchhash: "" }, { title: "gta vice city", searchhash: "" }, { title: "miami beach", searchhash: "" } ], [{ title: "miami beach", search_hash: "12456" }, { title: "time goes by", search_hash: "98765" } ] ] for (var i = 0; i < res[0].length; i++) { var res0 = res[0][i]; if (res0.searchhash === "") { var title = res0.title; for (var j=0;j<res[1].length;j++) { var res1 = res[1][j]; if (res1.title == title) res0.searchhash=res1.search_hash; } } } console.log(res) 

Answer 2

嗨，嘗試下面的代碼。

var res = [
  [{
      title: "time goes by",
      searchhash: ""
    },
    {
      title: "gta vice city",
      searchhash: ""
    },
    {
      title: "miami beach",
      searchhash: ""
    }
  ],

  [{
      title: "miami beach",
      search_hash: "12456"
    },
    {
      title: "time goes by",
      search_hash: "98765"
    }
  ]

]

for (var i = 0; i < res[0].length; i++) {
  if (res[0][i].searchhash === "") {
    titlePass(res[0][i]);
  }
}

function titlePass(o) {
  res[1].forEach((obj) => {
    if (o.title === obj.title) {
      o["searchhash"] = obj["search_hash"];
    }
  })
}