[英]Copy rows based on one cell value and in reference to another cell value and paste on a new sheet
它類似於我之前回答的問題。
您不必擔心創建工作表並命名它們,代碼會處理它。 它還會跳過參考表中未找到的項目。
它將描述項與參考表中的項匹配,然后將卡名稱與匹配項的類別名稱進行聯合 ,以便命名相關表。 如果此工作表不存在,則會創建並傳遞行數據,否則只需傳遞行數據。
Sub MyClients()
Dim lastrow As Long, lastcol As Long, matchrow As Long, i As Long, j As Long
Dim wsname As String
lastrow = Worksheets("Raw").Cells(Worksheets("Raw").Rows.Count, 1).End(xlUp).Row
lastcol = Worksheets("Raw").Cells(1, Worksheets("Raw").Columns.Count).End(xlToLeft).Column
Application.ScreenUpdating = False
For i = 2 To lastrow
On Error Resume Next
matchrow = Application.WorksheetFunction.Match(Worksheets("Raw").Cells(i, 10).Value, Worksheets("Reference").Range("A:A"), 0)
If Err.Number = 1004 Then
MsgBox "Couldn't find item: '" & Worksheets("Raw").Cells(i, 10).Value & "' within reference sheet. Skipping row no: " & i
GoTo skip:
End If
wsname = Worksheets("Raw").Cells(i, 3).Value & " - " & Worksheets("Reference").Cells(matchrow, 2).Value
On Error Resume Next
Worksheets(wsname).Cells(Worksheets(wsname).Rows.Count, 1).End(xlUp).Offset(1, 0) = Worksheets("Raw").Cells(i, 1).Value
For j = 1 To lastcol - 1
Worksheets(wsname).Cells(Worksheets(wsname).Rows.Count, 1).End(xlUp).Offset(0, j) = Worksheets("Raw").Cells(i, j).Value
Next j
If Err.Number = 9 Then
Sheets.Add(After:=Sheets(Sheets.Count)).Name = wsname
For j = 1 To lastcol
Worksheets(wsname).Cells(1, j) = Worksheets("Raw").Cells(1, j).Value
Next j
Worksheets(wsname).Cells(Worksheets(wsname).Rows.Count, 1).End(xlUp).Offset(1, 0) = Worksheets("Raw").Cells(i, 1).Value
For j = 1 To lastcol - 1
Worksheets(wsname).Cells(Worksheets(wsname).Rows.Count, 1).End(xlUp).Offset(0, j) = Worksheets("Raw").Cells(i, j).Value
Next j
End If
skip:
Next i
Worksheets("Raw").Activate
Application.ScreenUpdating = True
End Sub
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