[英]Get data from pivot table in view laravel
我的關系數據有很多問題,首先我會放我的模型和控制器,我使用laravel 5.3
模型列表地址
class ListsAddresses extends Model
{
protected $table = "addresses";
protected $fillable = ['state', 'city', 'street_number', 'neighborhood', 'cp'];
public function lists()
{
return $this->belongsToMany('App\Admin\Models\Lists', 'list_has_addresses' , 'address_id', 'list_id');
}
public function user(){
return $this->belongsTo('App\Admin\Models\User');
}
public $timestamps = false;
}
控制器列出地址
public function form_edit_address( $id_list, $id_address ){
$list = Lists::find( $id_list );
$address = ListsAddresses::find( $id_address );
return view( "admin.forms.form_edit_address" )
->with( 'list', $list )
->with( 'address', $address );
}
表格視圖
<div class="col-md-6" style="padding-right: 0">
<div class="form-group">
<label for="order">Orden*</label>
<input type="order" class="form-control" id="order" name="order" value="{{ $address->order }}" required>
</div><!-- /.form-group -->
</div><!-- /.col -->
我的數據庫表的數據庫具有下一個結構
id - title - order - list_id - address_id
如何在視圖中獲取與數據透視表中的地址對應的順序值?
EDDIT
這是我在創建新地址時保存訂單的方式
if( $address->save() ){
$address_data = array();
$address_title = htmlspecialchars( $request->input( "state" ).' '.$request->input( "city" ).' '.$request->input( "street" ).' '.$request->input( "neighborhood" ).' '.$request->input( "cp" ) );
$address_order = $request->input( "order" );
$address_data[ $address->id ] = array( 'title' => $address_title, 'order' => $address_order );
$list->addresses()->attach( $address_data );
}
也許首先將你的關系函數更改為withPivot('order')
public function lists()
{
return $this->belongsToMany('App\Admin\Models\Lists',
'list_has_addresses' , 'address_id', 'list_id')
->withPivot('order');
}
接下來,你完全分開獲取$ list和$ address,現在不能保證它們實際上是彼此相關的。 如果您沒有進行Route Model綁定,那么如果找不到任何東西,也許您應該有一些..OrFail()檢查以中止404:
public function form_edit_address( $id_list, $id_address )
{
$address = ListsAddresses::findOrFail( $id_address );
$list = $address->lists()->where('list_id', $id_list)->firstOrFail();
return view( "admin.forms.form_edit_address" )
->with( 'list', $list )
->with( 'address', $address );
}
我認為$ list對象將是具有pivot屬性的對象,所以在你的視圖中你可能會說$list->pivot->order
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.