[英]Download only specific folder in S3 bucket using python boto
下面的鏈接顯示了如何下載整個S3內容。 但是,如何獲得子文件夾的內容。 假設我的S3文件夾具有以下模擬結構。
S3Folder / S1 / file1.c
S3Folder / S1 / file2.h
S3Folder / S1 / file1.h
S3Folder / S2 / file.exe
S3Folder / S2 / resource.data
假設我只對S2文件夾感興趣。 如何隔離存儲桶列表中的鍵?
conn = boto.connect_s3(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY)
bucket = conn.get_bucket(bucket_name)
# go through the list of files
bucket_list = bucket.list()
for l in bucket_list:
keyString = str(l.key)
d = LOCAL_PATH + keyString
try:
l.get_contents_to_filename(d)
except OSError:
# check if dir exists
if not os.path.exists(d):
os.mkdir(d)
您可以執行以下操作:
import os
import boto3
s3_resource = boto3.resource("s3", region_name="us-east-1")
def download_objects():
root_dir = 'D:/' # local machine location
s3_bucket_name = 'S3_Bucket_Name' #s3 bucket name
s3_root_folder_prefix = 'sample' # bucket inside root folder
s3_folder_list = ['s3_folder_1','s3_folder_2','s3_folder_3'] # root folder inside sub folders list
my_bucket = self.s3_resource.Bucket(s3_bucket_name)
for file in my_bucket.objects.filter(Prefix=s3_root_folder_prefix):
if any(s in file.key for s in s3_folder_list):
try:
path, filename = os.path.split(file.key)
try:
os.makedirs(root_dir + path)
except Exception as err:
pass
my_bucket.download_file(file.key, root_dir + path + '/' + filename)
except Exception as err:
print(err)
if __name__ == '__main__':
download_objects()
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