PHP的：Mysqli_real_escape_string

Question

我這段代碼有問題，我看不出問題出在哪里。

    <?php 
require_once("config.php");
class MySQLDatabase{
    private $connection;
    function _construct(){
        $this->open_connection();
    }
    public function open_connection(){
        $this->connection=mysqli_connect(DB_SERVER,DB_USER,DB_PASS,DB_NAME);
        if(!$this->connection){
            Die("Database Connection Problem : ".mysqli_connect_errno()." : ".mysqli_connect_error());
        }
        }

    public function close_connection(){
        if(isset($this->connection)){
            mysqli_close($this->connection);
            unset($this->connection);
        }
    }
    public function query($sql){
        $sql=mysql_prep($sql);
        $result=mysqli_query($this->connection,$sql);
        confirm_query($result,$sql);
        return $result;
    }
    public function mysqli_prep($string){
        global $connection;
        $safe_string=mysqli_real_escape_string($this->connection,$string);
        return $safe_string;
    }
    private function confirm_query($result,$sql){
        if(!$result){
            Die("Database query Problem : ".$sql);
        }
    }

}
$database=new MySQLDatabase();
$db=& $database;
 ?>

我嘗試在Index.php上運行以下代碼

<?php
require_once("../includes/database.php");
echo "Is this working?";
echo $database->mysqli_prep("sss");
?>

但是我收到這個錯誤

警告：mysqli_real_escape_string（）期望參數1為mysqli，第29行的\\ includes \\ database.php中給出的null

Answer 1

錯誤是說您在MySQLDatabase::mysqli_prep()使用的$this->connection為null 。 那是因為它從未被初始化。

您的類構造函數需要以兩個下划線而不是一個下划線開頭：

function __construct(){
    $this->open_connection();
}