如何在Javascript中從多維數組轉換為一維對象？

Question

我有以下Javascript對象：

var data = {
  "customerSiteName": "Caldwell Sugar",
  "AgreementID": "0",
  "AgreementType": "",
  "AgreementTypeID": {
    "1": "Percentage Support",
    "2": "Consignment Support",
    "7": "Mobile Solutions",
    "9": "SmartGlance Subscription",
    "10": "Customer FIRST Lite",
    "11": "Solution Support - LPS",
    "12": "InSight Subscription"
  },
  "ProgramLevel": "",
  "CFProgramLevelID": [
    [1, "Primary"],
    [2, "Standard"],
    [3, "Premium"],
    [4, "Elite"]
  ],
  "DistributorID": "16",
  "StartDate": "",
  "EndDate": ""
};

我需要將作為數組的密鑰CFProgramLevelID轉換為一維對象。 這是我到目前為止所嘗試的：

$.each(data, function(key, value) {
    if (value !== null  && value instanceof Array) {
      var obj = dataObj = value.reduce((p, c, i) => (Array.isArray(c) && (p[i] ={[c.length - 1]: c[c.length - 1]}), p), {});

      console.log(obj);
    }
  });

但是CFProgramLevelID每個值都轉換為返回的對象：

Object {0: Object, 1: Object, 2: Object, 3: Object}
    0: Object
        1: "Primary"
        __proto__: Object
    1: Object
        1: "Standard"
        __proto__: Object
    2: Object
        1: "Premium"
        __proto__: Object
    3: Object
        1: "Elite"
        __proto__: Object

我想得到的是如下：

"CFProgramLevelID": {
    "1": "Primary",
    "2": "Standard",
    "3": "Premium",
    "4": "Elite"
  }

我做錯了什么？

我忘了提到我在這里創建了一個jsFiddle

Answer 1

更新了您的代碼，請參閱下面的內容（請注意，每個循環都會影響您對JSON密鑰對值的任何數組值，而不僅僅是CFProgramLevelID）：

 var data = { "customerSiteName": "Caldwell Sugar", "AgreementID": "0", "AgreementType": "", "AgreementTypeID": { "1": "Percentage Support", "2": "Consignment Support", "7": "Mobile Solutions", "9": "SmartGlance Subscription", "10": "Customer FIRST Lite", "11": "Solution Support - LPS", "12": "InSight Subscription" }, "ProgramLevel": "", "CFProgramLevelID": [ [1, "Primary"], [2, "Standard"], [3, "Premium"], [4, "Elite"] ], "DistributorID": "16", "StartDate": "", "EndDate": "" }; $.each(data, function(key, value) { if (value !== null && value instanceof Array) { var obj = dataObj = value.reduce((p, c, i) => (Array.isArray(c) && (p[i + 1] = c[c.length - 1]), p), {}); data[key] = obj; console.log(obj); console.log(data); } }); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> 

Answer 2

你可以這樣做;

 var data = { "customerSiteName": "Caldwell Sugar", "AgreementID": "0", "AgreementType": "", "AgreementTypeID": { "1": "Percentage Support", "2": "Consignment Support", "7": "Mobile Solutions", "9": "SmartGlance Subscription", "10": "Customer FIRST Lite", "11": "Solution Support - LPS", "12": "InSight Subscription" }, "ProgramLevel": "", "CFProgramLevelID": [ [1, "Primary"], [2, "Standard"], [3, "Premium"], [4, "Elite"] ], "DistributorID": "16", "StartDate": "", "EndDate": "" }, result = data.CFProgramLevelID.reduce((r,sa) => Object.assign(r,{[sa[0]]:sa[1]}), {}); console.log(result); 

Answer 3

請嘗試以下代碼。

 var objectConstructor = {}.constructor; var data = {} object = { "billing_address": { "billingAddress": "d", "billingCity": "e", "billingState": "f" }, "shipping_address": { "shippingAddress": "a", "shippingCity": "b", "shippingState": "c" } } a(object); function a(obj, key) { if (!obj) { return; } else if (obj.constructor !== objectConstructor) { data[key] = obj; } else { Object.keys(obj).map((key, index) => { a(obj[key], key); }) } } console.log(data) 

我希望它有所幫助。

謝謝。