[英]RSpec Routing Error w/ Nested Resources
我有一個規格,我認為應該沒有問題,但我認為,由於它是嵌套資源,因此可能會放棄我的要求。 我正在將Rails 4.2與Ruby 2.3.3一起使用。 這是怎么回事? 我知道這是一條有效路線,因為當我打rake routes
時出現
routes.rb
scope '/organizations/:organization_id' do
get 'dashboard', to: 'projects#dashboard'
resources :projects, except: [:delete] do
get 'configure', to: 'projects#configure'
post 'configure', to: 'projects#configure'
get 'team', to: 'projects#team'
get 'subprojects', to: 'projects#subprojects'
collection do
get 'search', to: 'projects#search'
get 'find', to: 'projects#find'
post 'create_by_sf_id', to: 'projects#create_by_sf_id'
end
resources :courses do
get 'module_progress', to: 'courses#module_progress'
get 'add_content', to: 'courses#add_content'
get 'summary', to: 'courses#summary'
post 'summary', to: 'courses#summary'
end
resources :tasks
end
end
projects_controller_spec.rb
describe 'GET project_team' do
it 'should render the project team page' do
get :team, organization_id: organization.id, id: project.id
expect(response.code).to eq '200'
end
end
projects_controller.rb
def team
@team = @project.project_team
end
... Aaa和導致的錯誤:
1) ProjectsController when authenticating as a customer GET project_team should render the project team page
Failure/Error: get :team, organization_id: organization.id, id: project.id
ActionController::UrlGenerationError:
No route matches {:action=>"team", :controller=>"projects", :id=>"460", :organization_id=>"417"}
# ./spec/controllers/projects_controller_spec.rb:90:in `block (4 levels) in <top (required)>'
您有嵌套在projects
下的team
,這使您:
project_team GET /organizations/:organization_id/projects/:project_id/team(.:format) projects#team
所以這:
get :team, organization_id: organization.id, id: project.id
應該可能是這樣的:
get :team, organization_id: organization.id, project_id: project.id
似乎您在這里可能還會遇到麻煩:
def team
@team = @project.project_team
end
因為您不查找@project
(除非您在before_action
掛鈎中進行此操作)。
最后,我很想創建一個ProjectTeamController
。 這樣,您可以使用show
方法代替非標准的team
方法。 但是,這是個人喜好問題。
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.