[英]How to pause a thread using wait and notify JavaFX
我不清楚如何使用wait()和notify()來暫停一個線程。 我讀過有關同步的討論,但我不確定如何在我的實例中執行此操作。 我有一個帶進度條的音樂播放器,我想暫停線程以控制進度條與音樂的同步。 這是我要暫停的主題:
@FXML private void clickedButton(ActionEvent event){
shuffle.setOnAction(e -> {
artistPane.setText(model.getCurrentSong());
if(firstTime){
//Multithreading with JavaFX. Essentially this other thread will check the slider to make sure its on track.
sliderThread = new Task<Void>() {
@Override
protected Void call() throws Exception {
boolean fxApplicationThread = Platform.isFxApplicationThread();
System.out.println("Is call on FXApplicationThread: " + fxApplicationThread);
//this is an infinite loop because now I only need to make this thread once, pausing and starting it, as opposed to making many threads
for(;;){
Thread.sleep(100);
progressBar.setValue(controller.getPercentageDone());
}
}
};
new Thread(sliderThread).start();
firstTime = false;
}else if(!model.getIsPlaying()){
//I want to start the thread here
}
controller.shuffle(); //this will start the music on the next song
});
這是下半場,我也想暫停並啟動線程:
play.setOnAction(e -> {
controller.play(); //this will pause/start the music
if(!model.getIsPlaying()){
//where I want to pause the thread.
}else{
//I want to start the thread here
}
});
我將嘗試給你一個簡單的例子,你試着將它應用到你的程序中......
public class TestClass extends JPanel {
/**
*
*/
private static final long serialVersionUID = 1L;
private Thread playThread ;
TestClass() {
playThread = new Thread(new Runnable() {
@Override
public void run() {
System.out.println("DO SOME THING HERE");
System.out.println("SONG WILL PLAY.....");
}
});
}
public void startMyPlayer() {
System.out.println("PLAYING NOW...");
playThread.start();
}
public void pauseMyPlayer() throws InterruptedException {
System.out.println("PAUSED NOW...");
playThread.wait();
}
public void resumeMyPlayer() {
System.out.println("RESUMING NOW...");
playThread.notify();
}
}
就是這樣。我希望這對你有所幫助。
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