[英]get between two date all days for every Month in PHP
我怎么能像這樣在兩天之間獲得兩天之間的所有日子
$dateStart = "2016/12/14";
$dateFin = "2017/04/21"
[2016/12/14 - 2016/12/31] => 17 days
[2017/01/01 - 2017/01/31] => 31 days
[2017/02/01 - 2017/02/28] => 28 days
[2017/03/01 - 2017/03/30] => 31 days
[2017/04/01 - 2017/04/21] => 21 days
您可以使用函數cal_days_in_month加上DateTime類:
<?php
$dateStart = new DateTime("2016/12/14");
$dateFin = new DateTime("2017/04/21");
$firstDay = $dateStart->format('Y/m/d');
$lastDay = $dateStart->format('Y/m/t');
$totalMonths = $dateStart->diff($dateFin)->m + ($dateStart->diff($dateFin)->y*12);
$result = [];
for ($i = 0; $i <= $totalMonths; $i++)
{
if ($i != 0){
$dateStart->modify('first day of next month');
$firstDay = $dateStart->format('Y/m/d');
$dateStart->modify('last day of month');
$lastDay = $dateStart->format('Y/m/t');
}
$nextDate = explode('/', $firstDay);
$totalDays = cal_days_in_month(CAL_GREGORIAN, $nextDate[1], $nextDate[2]);
if ($i == 0){
$totalDays -= $dateStart->format('d');
} else if ($i == $totalMonths) {
$totalDays = $dateFin->format('d');
}
$result["$firstDay - $lastDay"] = $totalDays;
}
var_dump($result);
缺乏改進,但給出了你的要求。
常規改進,請查看以下內容:
$dateStart = new DateTime("2016/12/14");
$dateFin = new DateTime("2017/04/21");
$totalMonths = $dateStart->diff($dateFin)->m + ($dateStart->diff($dateFin)->y*12);
$result = [];
for ($i = 0; $i <= $totalMonths; $i++)
{
if ($i != 0){
$obj = $dateStart->modify('first day of next month');
}
$firstDay = $dateStart->format('Y/m/d');
if ($i == $totalMonths){
$lastDay = $dateFin->format('Y/m/d');
} else {
$lastDay = $dateStart->format('Y/m/t');
}
$firstDayObj = strtotime($firstDay);
$lastDayObj = strtotime($lastDay);
$totalDays = (int) ceil(($lastDayObj - $firstDayObj) / 86400);
$totalDays = ((int) $dateStart->format('d') == 1) ? $totalDays + 1 : $totalDays;
$result["$firstDay - $lastDay"] = $totalDays;
}
var_dump($result);
//array(5) { ["2016/12/14 - 2016/12/31"]=> int(17) ["2017/01/01 - 2017/01/31"]=> int(31) ["2017/02/01 - 2017/02/28"]=> int(28) ["2017/03/01 - 2017/03/31"]=> int(31) ["2017/04/01 - 2017/04/21"]=> int(21) }
要獲得兩個日期的日期差異,您可以執行以下操作:
function daysDiff($d1, $d2)
{
$x1 = days($d1);
$x2 = days($d2);
if ($x1 && $x2) {
return abs($x1 - $x2);
}
}
function days(DateTime $x)
{
$y = $x->format('Y') - 1;
$days = $y * 365;
$z = (int)($y / 4);
$days += $z;
$z = (int)($y / 100);
$days -= $z;
$z = (int)($y / 400);
$days += $z;
$days += $x->format('z');
return $days;
}
$ d1和$ d2應該是DateTime類型,我從這里復制此代碼: http : //php.net/manual/es/function.date-diff.php#117691並進行了一些小修改以使用類型提示而不是使用get_class驗證變量類型
在這里查看演示
function dateDifference($date_1, $date_2, $differenceFormat = '%a')
{
$datetime1 = date_create($date_1);
$datetime2 = date_create($date_2);
$interval = date_diff($datetime1, $datetime2);
return $interval->format($differenceFormat);
}
請根據上述說明嘗試執行以下代碼段作為解決方案
$start_date = new DateTime('2016/12/14');
$start_date=$start_date->modify('+1 day');
$end_date = new DateTime('2017/04/21');
$end_date = $end_date->modify('+1 day');
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($start_date, $interval ,$end_date);
$month_days=array();
foreach($daterange as $date)
{
$date_month=$date->format('m');
$month_days[$date_month][]=$date->format('Y/m/d');
}
$result=array();
foreach($month_days as $days)
{
$begin=reset($days);
$end=end($days);
$result[$begin.'-'.$end]=count($days);
}
echo '<pre>';
print_r($result);
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.