在laravel中進行此查詢的最佳方法是什么？

Question

我正在laravel中從事我的第一個項目，現在我執行搜索功能，但是，我正在執行一個涉及多個左連接的查詢，當搜索返回時，我得到了一些多余的信息。

相關的表是這四個表，查詢如下：

$searchData = ProfessionalDetail::select('u.id as user_id','u.first_name','u.last_name','u.profile_pic','c.name as city_name','professional_details.avg_ratings')
    ->join('users as u' , 'u.id', '=' ,'professional_details.user_id')
    ->join('user_speciality as us' , 'us.user_id', '=' ,'professional_details.user_id')
    ->join('specialities as sp' , 'sp.id', '=' ,'us.speciality_id')
    ->join('cities as c' , 'c.id', '=' ,'professional_details.city_id')
    ->join('users_roles as ur' , 'ur.user_id', '=' ,'professional_details.user_id')
    ->where( function ( $q2 ) use ( $name) {
         $q2->where('u.first_name' , 'like', '%' . $name . '%')
         ->orWhere('u.last_name','like', '%'.$name.'%')
         ->orWhere('u.first_name','like',$name.'%');
         ->orWhere('sp.name','like',$name.'%');
    })
    ->where('ur.role_id' ,'=' , 2)
    ->paginate($num_per_page);

    return $searchData;[![demo][1]][1]

我嘗試過的是，按名稱或專業列出用戶（這是醫生頁面），按專業列出時，一切進展順利。 但是，當我要按用戶列出時，請左連接'user_speciality'和'professional_details'。 這使我多次回饋用戶。

例如：

public function testApi(Request $request)
{
    $users = ProfessionalDetail::searchByNameAndSpe("joshi", 10);
    $i = 0;
    if ($users) {
        foreach ($users as $key => $value) {
            $response["result"][] = $value;
            $response["total"] = $i++;
        }

    } else {
        return "error";
    }

    return $response;
}

返回：

{"result":[{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"Skin Specialist","city_name":"Pune","avg_ratings":"0.00"},{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"Heart Specialist","city_name":"Pune","avg_ratings":"0.00"},{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"ENT Specialist","city_name":"Pune","avg_ratings":"0.00"},{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"Kidney Specialist","city_name":"Pune","avg_ratings":"0.00"},{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"Eye Specialist","city_name":"Pune","avg_ratings":"0.00"}],"total":4}

Joshi僅注冊一次，但是我知道由於他擁有多個專業，由於“多對多”的關系，他將被無數次遣返。

現在，要按專業名稱和用戶名稱進行搜索，我知道的唯一方法是使用左連接，我認為分離信息的一種方法是在控制器中處理數組的信息，但是II我想知道這是否可以在查詢中解決，因為我對SQL不太了解，如果有什么辦法，我將不勝感激，因為它可以節省許多調試所有信息的步驟。

每種模型的方法

UserSpeciality表

public function users() {

    return $this->belongsToMany('App\User', 'user_speciality', 'speciality_id', 'user_id');
}

用戶

  public function userSpeciality() {
        return $this->belongsToMany('App\Speciality','user_speciality', 'user_id', 'speciality_id');
}

專業

public function users() {

    return $this->belongsToMany('App\User', 'user_speciality', 'user_id', 'speciality_id');
}

專業詳情表

    public function user(){
        return $this->belongsTo("App\User");
    }

Answer 1

嘗試一次按用戶ID分組

GROUPBY（USER_ID）