[英]How to fetch row values from mysql database and fill into text boxes by clicking radio button without refreshing page in php?
[英]How to fetch database values in html text boxes on button press without refreshing page in php?
我想在不刷新頁面的情況下將數據庫值提取到文本框中。 使用頁面刷新可以正常運行,但我不想刷新它。
我的代碼如下所示。
PHP
<?php include 'Connection.php'; $sql=mysqli_query($connect,"select * from `registration`"); while ($row=mysqli_fetch_array($sql)) { echo "<tr> <td>".$row['Emp_Code']."</td> <td>".$row['Full_Name']."</td> <td>".$row['Permanent_Address']."</td> <td>".$row['Mobile_No']."</td> <tr>"; if (isset($_POST['Fetchdetails'])) { $userid = $_POST['userid']; $fetchquery = mysqli_query($connect,"select * from `registration` where `Emp_Code` = '$userid'"); if (mysqli_num_rows($sql)>0) { while ($row=mysqli_fetch_array($fetchquery)) { $employeecode=$row['Emp_Code']; $fullname=$row['Full_Name']; $permanentaddress=$row['Permanent_Address']; $mobileno=$row['Mobile_No']; } } } } ?>
我的HTML代碼是
<html> <body> <div align="center" id="div"> <table width="400" border="1"> <tr align="right" style="background-color:#FFF;"> <td width="100">Permanent Address : </td> <td width="100"> <input type="text" name="permanentaddress" id="permanentaddress" placeholder="Permanent Address" size="15" value="<?php echo $permanentaddress;?>"/> </td> </tr> <tr align="right" style="background-color:#FFF;"> <td width="100">Employee Code : </td> <td width="100"> <input type="text" name="employeecode" id="employeecode" placeholder="Employee Code" size="15" value="<?php echo $employeecode;?>"/> </td> </tr> <tr align="right" style="background-color:#FFF;"> <td width="100">Full Name : </td> <td width="100"> <input type="text" name="fullname" id="fullname" placeholder="Full Name" size="15" value="<?php echo $fullname;?>"/> </td> </tr> <tr align="right" style="background-color:#FFF;"> <td width="100">Mobile No. : </td> <td width="100"> <input type="text" name="mobileno" id="mobileno" placeholder="Mobile No." size="15" value="<?php echo $mobileno;?>"/> </td> </tr> </table> </div> <br> <div align="center"> <input type="submit" name="Fetchdetails" value="Fetch Details" id="Fetchdetails" /> </div> </body> </html>
如何在不刷新網頁的情況下從數據庫取值到文本框中?
您可以使用AJAX實現數據的動態加載,例如:
$.ajax({
url: "yourscript.php",
cache: false,
success: function(html){
$("#results").append(html);
}
});
其中yourscript.php是您的后端腳本,將在其中執行數據庫調用,並在成功請求后返回您的成功。
請注意,數據應以序列化格式交換(對於AJAX請求,最常用的方法是JSON)。
您可以通過json實現。 請嘗試以下代碼。
PHP代碼
<?php
include 'Connection.php';
$userid = $_GET['userid'];
$fetchquery = mysqli_query($connect,"select * from `registration` where `Emp_Code` = '$userid'");
if (mysqli_num_rows($sql)>0)
{
while ($row=mysqli_fetch_array($fetchquery))
{
$return['employeecode']=$row['Emp_Code'];
$return['fullname']=$row['Full_Name'];
$return['permanentaddress']=$row['Permanent_Address'];
$return['mobileno']=$row['Mobile_No'];
}
}
echo json_encode($return);
JavaScript代碼
$("#Fetchdetails").click(function(e) {
e.preventDefault();
var userId = $(this).attr('data-user-id');
$.ajax({
type: "GET",
url : 'http://localhost/test/get_data.php?userid='+userId,
dataType : 'json',
success : function(response) {
$('#permanentaddress').val(response.permanentaddress);
$('#employeecode').val(response.employeecode);
$('#fullname').val(response.fullname);
$('#mobileno').val(response.mobileno);
},
error : function() {
alert('There was an error');
}
});
});
注意 :您必須將以下行替換為您的php文件url。
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