如何參數化抽象類中的變量

Question

我有下面的抽象類，其中取消了character_1，character_2，character_3。

public abstract class Properties {
 public static final String character_1 = "//*[@class='character- nav-slide-normal'][@alt='CHARLIE E LOLA']";
 public static final String character_2 = "//*[@class='character-nav-slide-normal'][@alt='PEPPA']";
 public static final String character_3 = "//*[@class='character-nav-slide-normal'][@alt='FESTA HI-5']";
}

我該如何參數化並傳遞給屬性。

String[] myStringArray = {"character_1","character_2","character_3"};
    for (int i = 0; i < myStringArray.length; i++)
    {
      String value = myStringArray[i];
        String altvalue =   driver.findElement(By.xpath(Properties.value)).getAttribute("alt");
        System.out.print(altvalue);
    }

Answer 1

您可以使用一個枚舉。 遵循以下原則

public enum Properties {

CHARACTER_1("//*[@class='character- nav-slide-normal'][@alt='CHARLIE E LOLA']"),
CHARACTER_2("//*[@class='character-nav-slide-normal'][@alt='PEPPA']"),
CHARACTER_3("//*[@class='character-nav-slide-normal'][@alt='FESTA HI-5']"),
CHARACTER_4("//*[@class='character-nav-slide-normal'][@alt='FESTA HI-5']"),
CHARACTER_5("//*[@class='character-nav-slide-normal'][@alt='FESTA HI-5']"),
CHARACTER_6("//*[@class='character-nav-slide-normal'][@alt='FESTA HI-5']"),
CHARACTER_7("//*[@class='character-nav-slide-normal'][@alt='FESTA HI-5']");

private String xpath;

Properties(String xpath) {
    this.xpath = xpath;
}

public String getXpath() {
    return xpath;
}

}

例

// Selective properties 
    Properties[] selectiveProperties = {Properties.CHARACTER_1, Properties.CHARACTER_3, Properties.CHARACTER_6, Properties.CHARACTER_7};

    for (Properties property : selectiveProperties) {
        String altvalue = driver.findElement(By.xpath(property.getXpath())).getAttribute("alt");
        System.out.print(altvalue);
    }


    //Iterate through all the properties 
    for (Properties property : Properties.values()) {
        String altvalue = driver.findElement(By.xpath(property.getXpath())).getAttribute("alt");
        System.out.print(altvalue);
    }

Answer 2

我想說的最簡單的是使用HashMap<String, String> 。

public class Properties { //no particular use to make this class abstract
    public static final Map<String, String> characters;
    static
    {
        characters = new HashMap<String, String>();
        characters.put("character_1", "//*[@class='character- nav-slide-normal'][@alt='CHARLIE E LOLA']");
        characters.put("character_2", "//*[@class='character-nav-slide-normal'][@alt='PEPPA']");
        characters.put("character_3", "//*[@class='character-nav-slide-normal'][@alt='FESTA HI-5']");
    }
}

//somewhere else...
String[] myStringArray = {"character_1","character_2","character_3"};
for (String stringArrayString : myStringArray)
{
    String xPath = Properties.characters.get(stringArrayString);
    String altvalue = driver.findElement(By.xpath(xPath)).getAttribute("alt");
    System.out.print(altvalue);
}

您可以輕松地使用上面的代碼來解決您的問題。

但是，您的報價表明您已經有了一些想法：

我需要如何將值（即myStringArray [i]）發送到Properties。 ???????? 因此，當i = 0時，字符串altvalue = driver.findElement（By.xpath（Properties.character_1））。getAttr‌ibute（“ alt”）; 當i = 1時，字符串altvalue = driver.findElement（By.xpath（Properties.character_2））。getAttr‌ibute（“ alt”）; 像那樣。

盡管反射是可能的，但強烈建議不要這樣做：您會失去編譯時類型的安全性，它在重構時會導致錯誤，並且性能會降低。