如何獲取今天的所有條目？

Question

嗨，即時通訊正在獲取今天日期的所有條目，我為此編寫了查詢，但我沒有獲得正確的條目。 請解決我的問題。下面我寫我的代碼。謝謝。

public ArrayList<groups> fetchByTodayDate(){

    String selectQuery = "SELECT * FROM " + DatabaseHelper.TABLE + " WHERE "+ DatabaseHelper.DATETIME + "<=date('now')";

    Cursor cursor = database.rawQuery(selectQuery,null);
    ArrayList<groups> all = new ArrayList<groups>();
    if (cursor != null && cursor.moveToFirst()) {
        do {
            groups data = new groups();
            smsdata.setMsgtext(cursor.getString(cursor.getColumnIndex(DatabaseHelper.TEXTMSG)));
            smsdata.setSmsId(cursor.getString(cursor.getColumnIndex(DatabaseHelper._ID)));

            all.add(data);
        } while (cursor.moveToNext());
    }
    cursor.close();
    return all;
}

Answer 1

（“ SELECT * FROM” + table_name +“ WHERE” + KEY_DATE +“ ='” +日期+“'”，空）；

Answer 2

對於今天的條目，請嘗試以下解決方案：-

String selectQuery = "SELECT * FROM " + DatabaseHelper.TABLE + " WHERE date(datetime("+ DatabaseHelper.DATETIME+"/1000, 'unixepoch','localtime'))=date('now')";

Answer 3

嘗試這個

public ArrayList<groups> fetchByTodayDate()
{
SQLiteDatabase db = this.getReadableDatabase();
ArrayList<groups> all = new ArrayList<>();

String selectQuery = "SELECT * FROM " + DatabaseHelper.TABLE;

Cursor cursor = db.rawQuery(selectQuery,null);

cursor.moveToFirst ();

while (!cursor.isAfterLast())
{
all.add(new groups (
cursor.getString(cursor.getColumnIndex(DatabaseHelper.TEXTMSG)),
cursor.getString(cursor.getColumnIndex(DatabaseHelper._ID))
));

cursor.moveToNext ();
}

cursor.close();
db.close();

return all;
}