如何在Ubuntu 16.04上的Laravel中使用Gulp

Question

我在項目中遇到了問題。 我安裝了節點，npm，gulp，並創建了文件gulpfile.js。

如果我使用命令gulp，則永遠不會發生任何事情。

我不知道什么是不對的。

請幫我。

我的代碼例如：

var gulp = require('gulp'),
    watch = require('gulp-watch'),
    sass = require('gulp-sass'),
    css_ = require('gulp-minify-css'),
    concat = require('gulp-concat'),
    livereload = require('gulp-livereload'),
    lr = require('tiny-lr'),
    clean = require('gulp-clean'),
    less = require('gulp-less'),
    server = lr();


var paths_css = {

    css: [  '/bower_components/AdminLTE/bootstrap/css/bootstrap.min.css',
            '/bower_components/AdminLTE/dist/css/AdminLTE.min.css',
            '/bower_components/AdminLTE/plugins/iCheck/flat/blue.css',
            '/bower_components/AdminLTE/plugins/morris/morris.css',
            '/bower_components/AdminLTE/plugins/jvectormap/jquery-jvectormap-1.2.2.css']
};


gulp.task('css', function() {
   return gulp.src(paths_css.css)
        .pipe(concat('css.css'))
        .pipe(sass())
        .pipe(gulp.dest('public/css/'));
});


gulp.task('default', ['css']);

Answer 1

嘗試這個：

var gulp = require('gulp'),
    watch = require('gulp-watch'),
    sass = require('gulp-sass'),
    css_ = require('gulp-minify-css'),
    concat = require('gulp-concat'),
    livereload = require('gulp-livereload'),
    lr = require('tiny-lr'),
    clean = require('gulp-clean'),
    less = require('gulp-less'),
    server = lr();


var paths_css = {

    css: [  'bower_components/AdminLTE/bootstrap/css/bootstrap.min.css',
            'bower_components/AdminLTE/dist/css/AdminLTE.min.css',
            'bower_components/AdminLTE/plugins/iCheck/flat/blue.css',
            'bower_components/AdminLTE/plugins/morris/morris.css',
            'bower_components/AdminLTE/plugins/jvectormap/jquery-jvectormap-1.2.2.css'] };


gulp.task('css', function() {    return gulp.src(paths_css.css)
        .pipe(concat('css.css'))
        .pipe(sass())
        .pipe(gulp.dest('public/css/')); });


gulp.task('default', ['css']);