[英]Retrieving data from a variable through http request
我是http請求和php的新手。 我有一個http:
xmlhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
var doc = xmlhttp.response;
myFunc(doc);
}
};
xmlhttp.open("GET",some.php",true);
xmlhttp.responseType = "document";
xmlhttp.send(null);
php文件:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title></title>
</head>
<body id="idk">
<?php
include("include1.inc");
include_once("include2.inc");
$cxn = mysqli_connect($host,$user,$passwd,$dbname) or die("Could not connect to the server at this time.");
$table = 'table';
$data = retrieveData($table, $cxn);//selects data from mysql db return array
var_dump($data);
?>
</body>
</html>
我如何從數據庫中獲取保存數組的數據變量? 當我轉儲或打印變量時,數組將被傳遞`responseText。 是否有一種更雄辯的方法來獲取該數組?
您將響應類型設置為“文檔”,因此您將獲得HTMLDocument作為響應。 因此,如果您只需要獲取數據變量,請嘗試通過以下方式更改代碼:javascript:
xmlhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
var doc = xmlhttp.response;
myFunc(doc);
}
};
xmlhttp.open("GET","some.php",true);
xmlhttp.responseType = "json";
xmlhttp.send();
和PHP:
<?php
include("include1.inc");
include_once("include2.inc");
$cxn = mysqli_connect($host,$user,$passwd,$dbname) or die("Could not connect to the server at this time.");
$table = 'table';
$data = retrieveData($table, $cxn);//selects data from mysql db return array
echo json_encode($data);
?>
請注意,在這種情況下,php腳本不包含任何html標記,而僅包含php代碼。
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