[英]Regex split string by spaces taking into account nested brackets
我知道這個問題已經被問過/回答過幾次,但是不幸的是,到目前為止,我嘗試過的所有解決方案都無法解決我的問題。 我需要這樣分割:
contrast(200%) drop-shadow(rgba(0, 0, 0, 0.5) 0px 0px 10px)
到這個:
contrast(200%)
drop-shadow(0px 0px 10px rgba(0,0,0,.5))
通過遵循此解決方案 ,我目前正在這樣做:
myString = "contrast(200%) drop-shadow(rgba(0, 0, 0, 0.5) 0px 0px 10px)"
myString.match(/[^\(\s]+(\(.*?\)+)?/g)
但這給了我:
contrast(200%)
drop-shadow(rgba(0, 0, 0, 0.5) <== notice the missing second ) here
0px <== unwanted, should go with previous one
0px <== unwanted, should go with previous one
10px) <== unwanted, should go with previous one
因為正則表達式不能捕獲所有的右括號...
這是我的解決方案:
function splitBySpaces(string){
var openBrackets = 0, ret = [], i = 0;
while (i < string.length){
if (string.charAt(i) == '(')
openBrackets++;
else if (string.charAt(i) == ')')
openBrackets--;
else if (string.charAt(i) == " " && openBrackets == 0){
ret.push(string.substr(0, i));
string = string.substr(i + 1);
i = -1;
}
i++;
}
if (string != "") ret.push(string);
return ret;
}
您可以使用以下代碼在嵌套括號之外的空格/制表符上拆分字符串:
function splitOnWhitespaceOutsideBalancedParens() { var item = '', result = [], stack = 0, whitespace = /\\s/; for (var i=0; i < text.length; i++) { if ( text[i].match(whitespace) && stack == 0 ) { result.push(item); item = ''; continue; } else if ( text[i] == '(' ) { stack++; } else if ( text[i] == ')' ) { stack--; } item += text[i]; } result.push(item); return result; } var text = "contrast(200%) drop-shadow(rgba(0, 0, 0, 0.5) 0px 0px 10px)"; console.log(splitOnWhitespaceOutsideBalancedParens(text));
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