[英]PHP sql statement where clause to multiple array values
如果value [3]存儲了多個數據,我該如何對數組使用where子句
$fsql="select * from Error where RptDatime = 201706091000 and partnumber like ('$value[3]')";
$getResults = $conn->prepare($fsql);
$getResults->execute();
$results = $getResults->fetchAll(PDO::FETCH_BOTH);
foreach($results as $row)
{
$mac = $row['Machine'];
$id = $row['Id'];
echo 'ID:'.$id.'Machine Number :'.$mac;
}
您可以使用regex函數代替like。 以下是適合您的示例代碼。
$partnumner = [];
foreach($value[3] as $v)
{
$partnumber[] = "*.".$v.".*";
}
$fsql="select * from Error where RptDatime = 201706091000 and partnumber REGEXP '".implode("|",$partnumber)."'";
如果您仍然希望使用like,可以在此處按照答案進行操作
我假設您有一個數字數組,因此,首先應驗證期望的數據,然后將其內含到逗號分隔的字符串中。
if(!isset($value[3])){
return false;
}
if(!is_array($value[3])){
return false;
}
foreach($value[3] as $number){
if(!is_numeric($number)){
return false;
}
}
$numbers = implode(",",$value[3]);
$fsql=sprintf("select * from Error where RptDatime = 201706091000 and partnumber in (%s)",$numbers);
$getResults = $conn->prepare($fsql);
$getResults->execute();
$results = $getResults->fetchAll(PDO::FETCH_BOTH);
foreach($results as $row)
{
$mac = $row['Machine'];
$id = $row['Id'];
echo 'ID:'.$id.'Machine Number :'.$mac;
}
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