[英]Simple program using Java Monitor
我有這個簡單的Java程序,它利用監視器讓客戶進入登機區。 我想我將wait()和notify()語句放在導致程序死鎖的錯誤位置,但是,我自己無法弄明白。 下面是我寫的代碼。
public class AdultCouple extends Thread
{
private boolean onRide = false;
private int ID;
AdultCouple(int ID)
{
this.ID = ID;
}
public synchronized void getIn()
{
while (!Main.isDoorOpen)
{
try
{
wait();
}
catch (InterruptedException ex)
{
}
System.out.println("Go through");
}
System.out.println("Couple " + ID + " get in boarding area.");
onRide = true;
Main.peopleInBoardingArea++;
notify();
}
public void run()
{
getIn();
}
}
public class Area extends Thread
{
Area()
{
}
public synchronized void openDoor()
{
while (Main.peopleInBoardingArea != 0)
{
try
{
wait();
}
catch (InterruptedException ex)
{
}
}
System.out.println("Area opens");
Main.isDoorOpen = true;
notifyAll();
}
public synchronized void closeDoor()
{
}
public void run()
{
openDoor();
}
}
public class ParentKid extends Thread
{
private boolean onRide = false;
private int ID;
ParentKid(int ID)
{
this.ID = ID;
}
public synchronized void getIn()
{
while (!Main.isDoorOpen)
{
try
{
wait();
}
catch (InterruptedException ex)
{
}
System.out.println("Go through");
}
System.out.println("Couple " + ID + " get in boarding area.");
onRide = true;
Main.peopleInBoardingArea++;
notify();
}
public void run()
{
getIn();
}
}
public class Main
{
public static boolean isDoorOpen = false;
public static int peopleInBoardingArea = 0;
public static void main(String args[])
{
Thread t3 = new Area();
Thread t1 = new ParentKid(1);
Thread t2 = new AdultCouple(2);
t1.start();
t2.start();
t3.start();
try
{
t1.join();
t2.join();
t3.join();
}
catch (InterruptedException ex)
{
}
}
}
問題是您在不同的對象上同步。 當你寫這樣的東西
public synchronized foo() {...}
你同步這個對象。 在您的情況下,您在當前線程上同步,這沒有任何意義。 您應該在同一個對象上同步。
public class Main {
public static Object lock = new Object();
...
}
public class AdultCouple extends Thread
{
private boolean onRide = false;
private int ID;
AdultCouple(int ID)
{
this.ID = ID;
}
public void getIn()
{
synchronized (Main.lock) {
while (!Main.isDoorOpen) {
try {
Main.lock.wait();
} catch (InterruptedException ex) {
}
System.out.println("Go through");
}
System.out.println("Couple " + ID + " get in boarding area.");
onRide = true;
Main.peopleInBoardingArea++;
Main.lock.notifyAll();
}
}
public void run()
{
getIn();
}
}
public class Area extends Thread
{
Area()
{
}
public void openDoor()
{
synchronized (Main.lock) {
while (Main.peopleInBoardingArea != 0) {
try {
Main.lock.wait();
} catch (InterruptedException ex) {
}
}
System.out.println("Area opens");
Main.isDoorOpen = true;
Main.lock.notifyAll();
}
}
public synchronized void closeDoor()
{
}
public void run()
{
openDoor();
}
}
public class ParentKid extends Thread
{
private boolean onRide = false;
private int ID;
ParentKid(int ID)
{
this.ID = ID;
}
public void getIn()
{
synchronized (Main.lock) {
while (!Main.isDoorOpen) {
try {
Main.lock.wait();
} catch (InterruptedException ex) {
}
System.out.println("Go through");
}
System.out.println("Kid " + ID + " get in boarding area.");
onRide = true;
Main.peopleInBoardingArea++;
Main.lock.notifyAll();
}
}
public void run()
{
getIn();
}
}
也不要使用notify()但使用notifyAll()。 我認為沒有理由使用它
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