[英]CASE statement in WHERE clause with != condition
我試圖弄清楚如何在where子句中使用case語句(使用!=),這里是我想要做的事情的想法:
SELECT *
FROM Table1 JOIN Table2 JOIN Table3
WHERE
CASE @fruit
WHEN 'Apples' THEN (What would go here to return only data related to apples in Table1?)
WHEN 'Citrus' THEN (What would go here to return data related to either oranges or lemons in Table2?)
WHEN 'Other' THEN (return all data not related to apples, oranges, or lemons from all 3 tables) (!=)
END
我在where子句中看到了一些case語句的例子,但沒有一個帶有!=條件的例子。 有任何想法嗎?
一個簡單的AND
/ OR
組合將:
SELECT *
FROM Table
WHERE
(@fruit != 'Other' AND Fruit = @fruit) OR
(@fruit = 'Other' AND Fruit NOT IN('Apples', 'Oranges')
如果我理解你的問題,你想要評估除了相等之外的其他布爾表達式。 CASE
語句有兩種形式,一種是你正在嘗試的(總是尋找相等)和另一種形式:
CASE
WHEN <boolean expression> THEN <result expression>
WHEN <boolean expression> THEN <result expression>
ELSE <else expression>
END
只需將ELSE用於其他一切
SELECT *
FROM Table
WHERE
CASE @fruit
WHEN 'Apples' THEN (What would go here to return only data related to apples?)
WHEN 'Oranges' THEN (What would go here to return only data related to oranges?)
ELSE (return all data not related to apples or oranges) (!=)
END
或者您可以使用案例中的參數,就像這樣
SELECT *
FROM Table
WHERE
CASE
WHEN @fruit = 'Apples' THEN (What would go here to return only data related to apples?)
WHEN @fruit = 'Oranges' THEN (What would go here to return only data related to oranges?)
WHEN @fruit <> 'Apples' AND @fruit <> 'Oranges' THEN (return all data not related to apples or oranges) (!=)
END
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