[英]Python sending files over socket
我想做一個文件調度程序,服務器將加載文件列表,然后與每個客戶端請求一一發送。 這個想法是在5台服務器之間分配許多文件的處理。
如何在每個客戶端連接中調用ClientThread類?
該腳本僅被編程為向每個客戶端請求發送相同的文件,我想要的是從每個客戶端請求中的文件列表發送不同的文件。
import socket
from threading import Thread
from socketserver import ThreadingMixIn
TCP_IP = '10.30.16.28'
TCP_PORT = 1006
BUFFER_SIZE = 1024
class ClientThread(Thread):
def __init__(self,ip,port,sock):
Thread.__init__(self)
self.ip = ip
self.port = port
self.sock = sock
print(" New thread started for "+ip+":"+str(port))
def run(self):
filename='log.VW.20170214a.log'
f = open(filename,'rb')
while True:
l = f.read(BUFFER_SIZE)
while (l):
self.sock.send(l)
l = f.read(BUFFER_SIZE)
if not l:
f.close()
self.sock.close()
break
tcpsock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
tcpsock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
tcpsock.bind((TCP_IP, TCP_PORT))
threads = []
with open("list.txt") as x: #File containing files list
lines=x.read().splitlines()
while True:
tcpsock.listen(5)
print("Waiting for incoming connections...")
(conn, (ip,port)) = tcpsock.accept()
print('Got connection from ', (ip,port))
newthread = ClientThread(ip,port,conn)
newthread.start()
threads.append(newthread)
for t in threads:
t.join()
import socket
TCP_IP = '10.30.16.28'
TCP_PORT = 1006
BUFFER_SIZE = 1024
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((TCP_IP, TCP_PORT))
with open('received_file', 'wb') as f:
print('file opened')
while True:
data = s.recv(BUFFER_SIZE)
if not data:
f.close()
print('file close()')
break
f.write(data)
print('Successfully get the file')
s.close()
print('connection closed')
我看不到這與線程或端口或類似的東西有什么關系。 更改此:
def __init__(self,ip,port,sock,fname):
Thread.__init__(self)
self.ip = ip
self.port = port
self.sock = sock
self.fname = fname
print(" New thread started for "+ip+":"+str(port))
def run(self):
f = open(self.fname,'rb')
當您上菜時:
with open("list.txt") as x: #File containing files list
lines=iter(x.read().splitlines())
最后:
newthread = ClientThread(ip,port,conn,lines.next().strip())
lines.next()
后將拋出StopIteration
異常,因此您必須處理該異常。
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