[英]SQL count query returning number of rows preset as 1 instead of actual number of rows
下面是從中獲取數據庫表中許多行的PHP代碼。 但是以下代碼始終將行數返回為1。 請幫助我解決問題,以從數據庫中獲取正確的行數。
$db=mysqli_connect("localhost","root","","test");
echo "<div class='row text-center col-lg-12' align='center'>";
$cmd="SELECT COUNT(*) FROM product WHERE product_name LIKE '%$search_query%'";
$result = mysqli_query($db, $cmd);
$total = mysqli_num_rows($result);
如果您執行SELECT COUNT(*)
您將返回到第一行的計數值所在的行。 因此,您需要像這樣獲得COUNT()
值:
$result = mysqli_query($db, $cmd);
$row = mysqli_fetch_array($result);
$total = $row[0];
這應該工作:
$db=mysqli_connect("localhost","root","","test");
echo "<div class='row text-center col-lg-12' align='center'>";
$cmd="SELECT * FROM product WHERE product_name LIKE '%$search_query%'";
$result = mysqli_query($db, $cmd);
$total = mysqli_num_rows($result);
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.