如何在數字猜謎游戲中循環時重新啟動

Question

我對此代碼有疑問。 我所看到的問題是，當用戶運行代碼並正確猜測或使用最大嘗試次數時，while循環不會啟動，並允許游戲重新啟動。 我的想法是將計數器（嘗試次數）重置為零，然后重新開始，但是我只是獲得帶有總得分的退出消息。

int guess = 0;
     int attempt = 0;
     int number = new Random().nextInt(1000) + 1;
     int scorePlayer = 0; int scoreComputer = 0;
     boolean repeat;

     System.out.println("Hello and welcome to the number guessing game.");
     System.out.println("Please guess a number between 1 and 1000");


    while(repeat == true){
         do{
             Scanner scan = new Scanner(System.in);
             guess = Integer.parseInt(scan.nextLine());
             System.out.println("The number you guessed is "+guess);
             attempt++;

             if(guess == number){
                 System.out.println("Congratulations! You got it!!");
                 scorePlayer++;
                 System.out.println("Would you like to play again? [YES/NO]");
                 Scanner a = new Scanner(System.in);
                 String answer = a.nextLine().toUpperCase();
                 if (answer != "YES"){
                     //repeat = false;
                     System.out.println("Thank you for playing");
                     System.out.println("The final score is "+scorePlayer+" to you and "+scoreComputer+" to the server");
                     if (scorePlayer<scoreComputer){
                         System.out.println("Computer wins!");
                     }else{
                         System.out.println("You win!");
                     }break;
                 }else{
                     attempt = 0;
                 }
             }else if(guess < number){
                 System.out.println("That is incorrect, try a larger number");

             }else if(guess > number){
                 System.out.println("That is incorrect, try a smaller number");

             }if(attempt == 10 && guess != number){
                 System.out.println("That is the max number of guesses allowed");
                 System.out.println("The number you were looking for is "+number);
                 scoreComputer++;
                 System.out.println("Would you like to play again? [YES/NO]");
                 Scanner b = new Scanner(System.in);
                 String answer = b.nextLine().toUpperCase();
                 if (answer != "YES"){
                     //repeat = false;
                     System.out.println("Thank you for playing");
                     System.out.println("The final score is "+scorePlayer+" to you and "+scoreComputer+" to the server");
                     if (scorePlayer<scoreComputer){
                         System.out.println("Computer wins!");
                     }else{
                         System.out.println("You win!");
                     }break;
                 }else{
                     attempt = 0;
                 }
             }

         }while(guess != number || attempt == 0);
         repeat = false;
    }

Answer 1

單“ =”是賦值運算符，只需將其更改為雙“ ==”。

while(repeat == true)

Answer 2

除了ugur所說的，您還可以做

while(repeat)

因為repeat是一個布爾變量（返回true或false）

Answer 3

檢查您設置了repeat=false的外循環中的最后一行。 因此，當您從內部循環break時， while檢查重復的while外部循環，每次除第一次外都為假。