[英]Hibernate + JPA Criteria API not setting parameters in Many-To-Many relationship query?
我在Schedule和Agent之間(通過屬性signedAgents)具有多對多關系。
我想查找包含我提供的任何代理的日程表。 我正在嘗試這樣做:
List<Agent> agentsToMatch = // ... I want schedules with any of these agents
CriteriaBuilder cb = session.getCriteriaBuilder();
CriteriaQuery<Schedule> query = cb.createQuery(Schedule.class);
Root<Schedule> schedule = query.from(Schedule.class);
query.where(schedule.get(Schedule_.assignedAgents).in( agentsToMatch ));
使用Hibernate 5.2.7,在數組中提供2個代理時,我得到以下查詢:
select generatedAlias0 from Schedule as generatedAlias0 where generatedAlias0.assignedAgents in (:param0, :param1)
但是,似乎沒有設置參數,因為出現以下異常:
WARN [qtp1782580546-44] o.h.engine.jdbc.spi.SqlExceptionHelper:129 - SQL Error: 0, SQLState: 22023
ERROR [qtp1782580546-44] o.h.engine.jdbc.spi.SqlExceptionHelper:131 - No value specified for parameter 1.
javax.persistence.PersistenceException: org.hibernate.exception.DataException: could not extract ResultSet
at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:147)
at org.hibernate.internal.ExceptionConverterImpl.convert(ExceptionConverterImpl.java:155)
at org.hibernate.query.internal.AbstractProducedQuery.list(AbstractProducedQuery.java:1419)
at org.hibernate.Query.getResultList(Query.java:427)
at org.hibernate.query.criteria.internal.compile.CriteriaQueryTypeQueryAdapter.getResultList(CriteriaQueryTypeQueryAdapter.java:72)
有什么想法我可能會出錯嗎?
我通過用.join替換.get來解決此問題:之前:
query.where(schedule.get(Schedule_.assignedAgents).in( agentsToMatch ));
后:
query.where(schedule.join(Schedule_.assignedAgents).in( agentsToMatch ));
正確的方法應該是
query.where(schedule.get(Schedule_.assignedAgents)
.in(cb.parameter(List.class, "agentsToMatch" );
然后您為查詢提供參數
query.setParameter("agentsToMatch", agentsToMatch);
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