R- knitr：kable - 如何顯示沒有列名的表格？

Question

目前，我有這個數據框（PS）：

我顯示此表的代碼是：

kable(PS) %>%
kable_styling(bootstrap_options = c("striped", "hover", "condensed", "responsive"))

我想顯示沒有列名的表，如下所示：

問題是

1）列名稱應為非空，並且嘗試使用空名稱將具有不受支持的結果

2）如果我轉換數據框並刪除列名，然后像這樣使用kable：

PS.mat <- as.matrix(PS)
colnames(PS.mat) <- NULL
kable(PS) %>%
kable_styling(bootstrap_options = c("striped", "hover", "condensed", "responsive"))

我收到以下錯誤

Error in kable_info$colnames[[length(kable_info$colnames)]] : attempt to select less than one element in integerOneIndex

我也嘗試了以下參數，但沒有結果

kable(PS, col.names = NA) 

編輯1：

一個可重復的例子：

if (!require(pacman)) install.packages("pacman")
p_load("lubridate","knitr","kableExtra","scales")

Statistics <- c("AUM",
            "Minimum Managed Account Size",
            "Liquidity",
            "Average Margin / Equity",
            "Roundturns / $ Million / Year",
            "Incentive Fees",
            "Instruments Traded")
Value <- c("$30K","$30K","Daily","50%","6,933","25%","ES")
AI <- data.frame(Statistics,Value);
kable(AI) %>%
kable_styling(bootstrap_options = c("striped", "hover", "condensed", "responsive"))

Answer 1

根據您所需的輸出格式，您可以使用這些功能。 對於pandoc：

x = kable(AI, format="pandoc") %>%
    kable_styling(bootstrap_options = c("striped", "hover", "condensed", "responsive"))
cat(x[3:9], sep="\n")

對於HTML：

x = kable(AI, format="html") %>%
    kable_styling(bootstrap_options = c("striped", "hover", "condensed", "responsive"))
gsub("<thead>.*</thead>", "", x)