過濾包含對象數組的對象

Question

我想根據輸入的關鍵字過濾數據。

https://jsfiddle.net/LeoCoco/e96L8akn/

let keyword = '-pre';

let data = {
  'Basic': [{
    name: 'a-basic'
  }, {
    name: 'b-basic'
  }, {
    name: 'c-basic'
  }],
  'Premium': [{
    name: 'a-pre'
  }, {
    name: 'b-pre'
  }, {
    name: 'c-pre'
  }],
  'Extra': [{
    name: 'a-ext'
  }, {
    name: 'b-ext'
  }, {
    name: 'c-ext'
  }],
};

輸出量

'Premium': [{name: 'a-pre'}, { name: 'b-pre'}, { name: 'c-pre'}]

我的嘗試

lodash.forEach(data, (card) => {
  card = card.filter(o => {
    return Object.keys(o).some(k => {
      return typeof o[k] === 'string' && o[k].toLowerCase().includes(keyword.toLowerCase());
    });
  });
})

但這是行不通的，對我來說困難在於篩選必須在每個數組中包含的嵌套對象鍵上進行。

Answer 1

因為這是對象，所以可以在Object.keys() reduce()上使用reduce() ，然后在內部使用every()來檢查關鍵字。

 let keyword = '-pre'; let data = {"Basic":[{"name":"a-basic"},{"name":"b-basic"},{"name":"c-basic"}],"Premium":[{"name":"a-pre"},{"name":"b-pre"},{"name":"c-pre"}],"Extra":[{"name":"a-ext"},{"name":"b-ext"},{"name":"c-ext"}]} var result = Object.keys(data).reduce(function(r, e) { var check = data[e].every(o => o.name.indexOf(keyword) != -1); if(check) r[e] = data[e] return r; }, {}) console.log(result) 

Answer 2

 var result={};
 Object.keys(data).forEach(key => {
   result[key] = data[key].filter(o => {
       return Object.keys(o).some(k =>typeof o[k] === 'string' && o[k].toLowerCase().includes(keyword.toLowerCase()));
  });
})